將嵌套列表中的所有元素轉換為整數

Question

我有一個以整數作為字符串的列表，所以如何將其轉換回

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]

我試圖使用列表理解

[j for j in i if j.isdigit() for i in lst ]

但它返回

['3', '3', '3', '3', '3', '3', '4', '4', '4', '4', '4', '4']

所需的輸出：

[[1,2],[2,4],[1,4],[1,5],[3,5],[3,4]]

有什么幫助嗎？

Answer 1

使用ast模塊。

例如：

import ast

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
res = [list(map(int, ast.literal_eval(i))) for i in lst]
print(res)

輸出：

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 2

天真的解決方案：

>>> lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
>>> [[int(x.strip("'")) for x in s[1:-1].split(',')] for s in lst]
[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 3

您可以使用ast模塊的literal_eval函數和列表理解

>>>[[int(j) for j in ast.literal_eval(i)] for i in lst]

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]

Answer 4

final_lst = []


for s in lst:
  sublist = []
  for item in eval(s):
     sublist.append(int(item))
  final_lst.append(sublist)

print(final_lst) 

Answer 5

您只需eval主列表中的每個列表，然后解析子lista中的每個int

lst = ["['1','2']", "['2','4']", "['1','4']", "['1','5']", "['3','5']", "['3','4']"]
x = [[int(j) for j in eval(i)] for i in lst]
print (x)

輸出

[[1, 2], [2, 4], [1, 4], [1, 5], [3, 5], [3, 4]]