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Python Pandas从列表中将多个SAS文件读取到单独的数据框中

[英]Python Pandas Read multiple SAS files from a list into separate dataframes

I'm reading a bunch of SAS files like so: 我正在读取许多SAS文件,如下所示:

demography = pd.read_sas("demography.sas7bdat", encoding = 'latin-1') adverse_event_ds = pd.read_sas("adverse_event_ds.sas7bdat", encoding = 'latin-1') rpt10344 = pd.read_sas("rpt10344.sas7bdat", encoding = 'latin-1') vaccine_administration = pd.read_sas("vaccine_administration.sas7bdat", encoding = 'latin-1') lab_tests_blood_chemistry_ds = pd.read_sas("lab_tests_blood_chemistry_ds.sas7bdat", encoding = 'latin-1') lab_tests_hematology_ds = pd.read_sas("lab_tests_hematology_ds.sas7bdat", encoding = 'latin-1') lab_tests_miscellaneous_ds = pd.read_sas("lab_tests_miscellaneous_ds.sas7bdat", encoding = 'latin-1') vital_signs = pd.read_sas("vital_signs.sas7bdat", encoding = 'latin-1')

I want to be able to replace it with something like this: 我希望能够将其替换为以下内容:

datasets = ["demography", "adverse_event_ds", "rpt10344", "vaccine_administration", "lab_tests_blood_chemistry_ds", "lab_tests_hematology_ds", "lab_tests_miscellaneous_ds", "vital_signs"]

for dataset in datasets: dataset = pd.read_sas(dataset+".sas7bdat", encoding = 'latin-1')

But when I do something like: demography.info() 但是当我做类似的事情时: demography.info()

I get: NameError: name 'demography' is not defined 我得到: NameError: name 'demography' is not defined

What's happening under the hood and how can I fix this? 到底发生了什么,我该如何解决?

this is assigning to dataset on every iteration rather than creating the new variables (eg demography , rpt10344 , etc). 这是在每次迭代时分配给dataset ,而不是创建新变量(例如, demographyrpt10344等)。

i'd use a dataset dictionary as follows: 我将使用数据集字典,如下所示:

dsd = {}
for dataset in datasets:
    dsd[dataset] = pd.read_sas(dataset+".sas7bdat", encoding = 'latin-1')

or a more pythonic route: 或更Python的路线:

dsd = { d : pd.read_sas(d + ".sas7bdat", encoding = 'latin-1') for d in datasets }

I'd strongly advise against assigning to individual variable names for reasons explained here and here but if you absolutely must you can use 我强烈建议您不要出于此处此处说明的原因而为各个变量名分配变量,但是如果您绝对必须可以使用

for d in datasets:
    globals()[d] = pd.read_sas(d + ".sas7bdat", encoding = 'latin-1')

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