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将静态库链接到MSVC中的共享库会导致无法解析的符号

[英]Linking a static library to a shared library in MSVC causes unresolved symbol

I'm building a dynamic library c which is linked to a static library b . 我正在构建一个链接到静态库b动态c

The static library b is statically linked to the static library a . 静态库b静态链接到静态库a

The cmake for c , roughly looks like this (the cmakes for a and b are quite similar): c的cmake大致如下所示( ab的cmake非常相似):

cmake_minimum_required(VERSION 2.6)
project(c)

include_directories(../b/src)
link_directories(../b/Debug)

add_library(c SHARED src/c.cpp)
target_link_libraries(c PRIVATE b)

The issue I'm facing is related to the fact that c can't see references to functions defined in a : 我面临的问题与c无法看到对在a定义的函数的引用有关:

b.lib(b.obj) : error LNK2019: unresolved external symbol "int __cdecl a(void)" (?a@@YAHXZ) referenced in function "int __cdecl b(void)" (?b@@YAHXZ) [C:\Users\user\Workspace\garbage\c\c.vcxproj]
C:\Users\user\Workspace\garbage\c\Debug\c.dll : fatal error LNK1120: 1 unresolved externals [C:\Users\user\Workspace\garbage\c\c.vcxproj]

Is there any way for c to properly link? c有什么方法可以正确链接吗?

Related questions: 相关问题:

Linking static libraries to other static libraries 将静态库链接到其他静态库

Something tells me that your linker output is not quite right. 告诉我您的链接器输出不正确。 It looks like perhaps a and b are trying to be exported classes. 似乎ab试图导出类。

That aside, this line tells us that b cannot actually see some symbol (perhaps the class default constructor) for library (class) a : 除此之外,这一行告诉我们b实际上看不到库(类) a某些符号(也许是类的默认构造函数):

b.lib(b.obj) : error LNK2019: unresolved external symbol "int __cdecl a(void)" (?a@@YAHXZ) referenced in function "int __cdecl b(void)" (?b@@YAHXZ)

In fact, your CMake example never links a to b and, your original questions says that b is linked into a . 实际上,您的CMake示例从不将a链接到b并且您最初的问题是b链接到a If you mean what you said in your question, you linker shows the logic error. 如果您的意思是您在问题中所说的,则链接程序将显示逻辑错误。

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