比较两个元组列表，然后返回true / false

Question

lst = [('NOUN', 'chip'), ('NOUN', 'potato'), ('potato', 'chip')]

permute_lst = [('NOUN', 'chip'), ('potato', 'chip'), ('potato', 'bbq'), ('NOUN', 'potato'), ('potato', 'crisp')]

I want to compare these two lists of tuples in a self-defined function to return a list of Booleans. My current code:

def get_tf(lst):
  tf_list = []
  for lookup in permute_lst:
    if set(lst) == set(lookup):
        tf_list.append(True)
    else:
        tf_list.append(False)
  return tf_list

The result tf_list=[False, False, False, False, False]

My expected result is like:

tf_list = [True, True, False, True, False]

Answer 1

Use a list comprehension that simply checks to see whether each of your permute_list items is in the reference list:

return [pair in lst for pair in permute_lst]

Output:

[True, True, False, True, False]