[英]Comparing two lists returns True even though it needs to return False
[英]compare two tuple lists and then return true/false
lst = [('NOUN', 'chip'), ('NOUN', 'potato'), ('potato', 'chip')]
permute_lst = [('NOUN', 'chip'), ('potato', 'chip'), ('potato', 'bbq'), ('NOUN', 'potato'), ('potato', 'crisp')]
我想在自定義函數中比較這兩個元組列表,以返回布爾值列表。 我當前的代碼:
def get_tf(lst):
tf_list = []
for lookup in permute_lst:
if set(lst) == set(lookup):
tf_list.append(True)
else:
tf_list.append(False)
return tf_list
結果tf_list=[False, False, False, False, False]
我的預期結果是:
tf_list = [True, True, False, True, False]
使用列表permute_list
,該列表permute_list
僅檢查每個permute_list
項目是否在參考列表中:
return [pair in lst for pair in permute_lst]
輸出:
[True, True, False, True, False]
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