我在python中正确解释此列表理解吗？

Question

I am still fairly new to python and still have some fumbles when reading list comprehensions. I tried translating two list comprehensions I saw in a tutorial into its elongated form. Did I translate correctly?

list comprehension 1

mytokens = [ word.lemma_.lower().strip() if word.lemma_ != "-PRON-" else word.lower_ for word in mytokens ]

translation 1

for word in mytokens:
    if word.lemma_ != "-PRON-":
        word.lemma_.lower().strip()
    else:
        word.lower_

list comprehension 2

mytokens = [ word for word in mytokens if word not in stopwords and word not in punctuations ]

translation 2

for word in mytokens:
    if word not in stopwords and not in punctuations:
        yield word

for translation 2, I dont think "yield word" would be correct since its not a definition. I am guessing list comprehension 2 does the if statement and places the word back into the list mytokens so maybe it should be a .append?

Answer 1

I think it is right. You are looping correctly. However, you aren't adding the words to a list? Do you mean to be doing this?

So for the first one you could use

my_list = []
for word in mytokens:
    if word.lemma_ != "-PRON-":
        my_list.append(word.lemma_.lower().strip())
    else:
        my_list.append(word.lower_)

By adding them to a list like this it means you can directly compare the output of your translation and the output of the list comprehension. mytokens should be exactly the same as my_list if done correctly.

Also there is a small mistake in the second translation. It should be:

for word in mytokens:
    if word not in stopwords and word not in punctuations:
        yield word

You could also modify this second translation to add all your words to a list.

Answer 2

Let's simplify this:

coll = ["Gerry", "Mary", "Sue"]

comprehended = [ word.lower() for word in coll]

def comprehender(coll):
  coll_out = []
  for word in coll:
      coll_out.append(word.lower())
  return coll_out

If you run this, you can be assured that the two are equivalent by using assert or just return ing comprehended == comprehender(coll)

This is a valid sanity check you can do on any list comprehension, you just vary this pattern to match the logic of your comprehension.