简体   繁体   English

在ggplot2中绘制数据框的列表

[英]Plot data frame's lists in ggplot2

I have a data.table / data frame with lists as values. 我有一个data.table /数据框,其中的列表作为值。 I would like to make a box or violin plot of the values, one violin/box representing one row of my data set, but I can't figure out how. 我想对这些值制作一个盒子或小提琴图,一个小提琴/盒子代表我的数据集的一行,但是我不知道怎么做。

Example: 例:

test.dt <- data.table(id = c('a','b','c'), v1 = list(c(1,0,10),1:5,3))
ggplot(data = test.dt, aes(x = as.factor(id), y = v1)) + geom_boxplot()

I get the following message: 我收到以下消息:

Warning message: Computation failed in stat_boxplot() : 'x' must be atomic 警告消息: stat_boxplot()计算失败:“ x”必须是原子的

So my guess is that maybe I should split the lists of the values to rows somehow. 所以我的猜测是,也许我应该以某种方式将值列表拆分为行。 Ie: the row with a as id would be transformed to 3 rows (corresponding to the length of the vector in v1 ) with the same id, but the values would be split among them. 即: 作为ID的行会被变换为3行(对应于V1的矢量的长度)具有相同id,但值将它们之间进行分割。

Firstly I don't know how to transform the data.table as mentioned, secondly I don't know either if this would be the solution at all. 首先,我不知道如何转换提到的data.table,其次,我也不知道这是否是解决方案。

Indeed, you need to unnest your dataset before plotting: 实际上,在绘制之前,您需要unnest数据集:

library(tidyverse)

unnest(test.dt) %>% 
ggplot(data = ., aes(x = as.factor(id), y = v1)) + geom_boxplot()

I believe what you are looking for is the very handy unnest() function. 我相信您正在寻找的是非常方便的unnest()函数。 The following code works: 以下代码有效:

library(data.table)
library(tidyverse)

test.dt <- data.table(id = c('a','b','c'), v1 = list(c(1,0,10),1:5,3))
test.dt = test.dt %>% unnest()

ggplot(test.dt, aes(x = as.factor(id), y = v1)) + 
  geom_boxplot()

If you don't want to import the whole tidyverse, the unnest() function is from the tidyr package. 如果您不想导入整个tidyverse,则unnest()函数来自tidyr包。

This is what unnest() does with example data: 这是unnest()对示例数据的处理:

> data.table(id = c('a','b','c'), v1 = list(c(1,0,10),1:5,3))
   id        v1
1:  a   1, 0,10
2:  b 1,2,3,4,5
3:  c         3
> data.table(id = c('a','b','c'), v1 = list(c(1,0,10),1:5,3)) %>% unnest()
   id v1
1:  a  1
2:  a  0
3:  a 10
4:  b  1
5:  b  2
6:  b  3
7:  b  4
8:  b  5
9:  c  3

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM