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makefile即使没有任何更改也可以执行目标

[英]makefile performs target even without any changes

I have a simple makefile that works fine, but it seems to perform the all target even if no changes occurred. 我有一个可以正常工作的简单makefile ,但是即使没有发生任何更改,它似乎也可以执行all目标。 I would expect a 我期望一个

make: Nothing to be done for 'all'.

Message, but it keeps executing the target whenever I call make . 消息,但是每当我调用make时,它都会继续执行目标。 Here is my simple makefile: 这是我的简单makefile:

BASEDIR = /home/someuser/STA
SRC_DIR = ${BASEDIR}/src
OBJ_DIR = ${BASEDIR}/obj
INC_DIR = ${BASEDIR}/inc

SRC_FILES        = $(wildcard  ${SRC_DIR}/*.cpp)
SRC_FILES_NOTDIR = $(notdir    ${SRC_FILES})
OBJ_FILES_NOTDIR = $(patsubst  %.cpp, %.cpp.o, ${SRC_FILES_NOTDIR})
OBJ_FILES        = $(addprefix ${OBJ_DIR}/,${OBJ_FILES_NOTDIR})
INC_FILES        = $(wildcard  ${INC_DIR}/*.h)

all: ${OBJ_FILES}
    g++ ${OBJ_FILES} -o program

${OBJ_DIR}/%.cpp.o: ${SRC_DIR}/%.cpp ${INC_FILES}
    g++ -I${INC_DIR} -o $@ -c $<

And here is what printed to terminal when I call make twice: 这是我两次拨打make时打印到终端的内容:

$ make
g++ <somedir/file1>.cpp.o <somedir/file2>.cpp.o -o program
$ make
g++ <somedir/file1>.cpp.o <somedir/file2>.cpp.o -o program

Replace all that is not a file and does not exist (reason why make tries to build it each time) by program , a real file that make can see. 更换all这不是一个文件,不存在(之所以做出尝试构建各一次)的program ,一个真正的文件,使可以看到。 If you really want an all symbolic target, declare it as phony and add a rule without recipe to tell make that all depends on program : 如果您真的想要一个all符号目标,请将其声明为phony,并添加一个不带配方的规则,以告知all取决于program

.PHONY: all
all: program

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