[英]Python - special characters reading from URL parameter
I am reading URL parameter from the below URL 我正在从下面的URL中读取URL参数
http://exaple.com/api/v1/get_example/?fruits_name=[apple%20+%20banana]
fruits = urllib.unquote(request.GET.get('fruits_name', None)).decode('utf8')
print fruits
my output is: [apple banana]
in between apple and banana I am getting three spaces but not +
symbol in my output. 我的输出是:
[apple banana]
在苹果和香蕉之间,我的输出中得到三个空格,但没有+
符号。 the original string is [apple + banana]
. 原始字符串是
[apple + banana]
。 I need output as [apple + banana]
. 我需要输出为
[apple + banana]
。
Can anyone suggest where I am doing wrong?? 谁能建议我做错了什么?
You could split query string on your own to preserve the plus sign: 您可以自行拆分查询字符串以保留加号:
from urllib.parse import urlparse, unquote
u = 'http://exaple.com/api/v1/get_example/?fruits_name=[apple%20+%20banana]'
o = urlparse(u)
qs = unquote(o.query)
queryDict = {k: v for (k, v) in [x.split("=", 1) for x in qs.split("&")]}
print(queryDict)
Prints: 打印:
{'fruits_name': '[apple + banana]'}
Replace special characters in string using the %xx escape. 使用%xx转义符替换字符串中的特殊字符。 Letters, digits, and the characters '_.-' are never quoted.
字母,数字和字符“ _.-”都不会被引用。 By default, this function is intended for quoting the path section of the URL.The optional safe parameter specifies additional characters that should not be quoted — its default value is '/'
默认情况下,此函数用于引用URL的路径部分。可选的safe参数指定不应引用的其他字符-其默认值为'/'
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