[英]Is this the correct way to read FFT of a audio file? (python + wav)
The audio file is a 16bit mono PCM audio file with varying samplerates and length of 10-30ms. 音频文件是16位单声道PCM音频文件,具有不同的采样率,长度为10-30ms。
import struct
from pydub import AudioSegment
import numpy as np
import matplotlib.pyplot as plt
import scipy.fftpack
sound = AudioSegment.from_wav("3000hz.wav")
raw_data = sound.raw_data# needs to be mono
sample_rate = sound.frame_rate
sample_size = sound.sample_width
channels = sound.channels
fmt = "%ih" % sound.frame_count() * channels
amplitudes= struct.unpack(fmt, raw_data)
yVals = scipy.fftpack.fft(amplitudes)
plt.plot(abs(yVals[:(len(yVals)/2)-1]),'r')
plt.show()
The output with a 3000hz wav file(taken from an online sin wave generator) results in a decent looking FFT but spikes at 9000, not 3000. This off by a factor of 3 is consistent in other tests. 带有3000hz wav文件的输出(来自在线正弦波发生器)产生了不错的FFT,但峰值为9000,而不是3000。在其他测试中,相差3倍是一致的。 Is this ok? 这个可以吗? And is the code correct? 代码正确吗?
By calling plt.plot()
with only an y
array and no corresponding x
array, it will use 0, 1, ..., N-1
as the x
values. 通过仅使用y
数组而没有对应的x
数组调用plt.plot()
,它将使用0, 1, ..., N-1
作为x
值。 This is not what we actually want, we want the frequency on the x-axis. 这不是我们真正想要的,我们想要x轴上的频率。
Let's denote the x
value you see in the plot right now by "bin index". 让我们用“ bin index”表示您现在在图中看到的x
值。 Let the length of the array be N
and the sampling frequency be fs
. 假设数组的长度为N
,采样频率为fs
。 When calculating an FFT, the bin index 0
corresponds to a frequency of 0 Hz. 在计算FFT时,bin索引0
对应于0 Hz的频率。 The next bin index 1
corresponds to the frequency fs / N
Hz. 下一个二进制索引1
对应于频率fs / N
Hz。 This is because the FFT will have N
values and go from 0
Hz to fs
Hz, so each step is fs / N
Hz. 这是因为FFT将具有N
值,并且从0
Hz到fs
Hz,因此每个步都是fs / N
Hz。 The next bin thus corresponds to 2 * fs / N
Hz, and so on. 因此,下一个bin对应于2 * fs / N
Hz,依此类推。 And the last bin N-1
is (N-1)/N * fs
Hz, so almost fs
Hz. 而最后一个N-1
箱是(N-1)/N * fs
Hz,所以几乎是fs
Hz。
If we want to create a plot where you have amplitude spectrum vs. frequency, then we need to manually create a frequency vector which contains the real frequency for each bin index. 如果要创建一个振幅谱与频率关系图,则需要手动创建一个频率矢量,其中包含每个仓位索引的实际频率。 Luckily, scipy.fftpack
contains a function for that: fftfreq
: 幸运的是, scipy.fftpack
包含了以下功能: fftfreq
:
freq = scipy.fftpack.fftfreq(n=N, d=1.0 / fs)
Then we can modify the call to plt.plot()
to use freq
as the x
values instead of 0 ... N-1
: 然后,我们可以修改对plt.plot()
的调用,以将freq
用作x
值而不是0 ... N-1
:
plt.plot(freq, abs(yVals), 'r')
With that, the peak should be at the correct position. 这样,峰值应该在正确的位置。
If you only want to see a single-sided spectrum, then you can crop both freq
and yVals
like you already do in the code in the question. 如果您只想查看单面频谱,则可以像在问题代码中已经yVals
那样对freq
和yVals
进行裁剪。
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