运行具有多个参数的 python 函数

Question

I have a function here:

def ROC(dfH, n):  
    M = dfH['Close'].diff(n - 1)  
    N = dfH['Close'].shift(n - 1)  
    ROC = pd.Series(M / N, name = 'ROC_' + str(n))  
    dfH = dfH.join(ROC)  
    return dfH

With the above function I want to make multiple columns by changing the value of n so i run the code

a = (4, 8)
for j in a:
    ROC(dfH, n=a)

which gets to be wrong. please help thanks in advance.

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Answer 1

a = (4, 8)
for j in a:
    ROC(dfH, n=a)
               ^

You are using a instead of j in the for loop.