使用迭代器将单词中的两个部分串联在一起

Question

I need to concatenate certain words that appear separated in a list of words, such as "computer" (below). These words appear separated in the list due to line breaks and I want to fix this.

lst=['love','friend', 'apple', 'com', 'puter']

the expected result is:

lst=['love','friend', 'apple', 'computer']

My code doesn't work. Can anyone help me to do that?

the code I am trying is:

from collections import defaultdict
import enchant
import string
words=['love', 'friend', 'car', 'apple', 
'com', 'puter', 'vi']
myit = iter(words)
dic=enchant.Dict('en_UK')
lst=[]

errors=[]

for i in words:

   if  dic.check(i) is True:

      lst.append(i)
   if dic.check(i) is False:

      a= i + next(myit)

   if dic.check(a) is True:

      lst.append(a)

   else:

     continue



print (lst)`

Answer 1

The main problem with your code is that you are, on the one hand, iterating words in the for loop and, on the other hand, through the iterator myit . These two iterations are independent, so you cannot use next(myit) within your loop to get the word after i (also, if i is the last word there would be no next word). On the other hand, your problem can be complicated by the fact that there may be split words with parts that are too in the dictionary (eg printable is a word, but so are print and able ).

Assuming a simple scenario where split word parts are never in the dictionary, I think this algorithm could work better for you:

import enchant

words = ['love', 'friend', 'car', 'apple', 'com', 'puter', 'vi']
myit = iter(words)
dic = enchant.Dict('en_UK')
lst = []
# The word that you are currently considering
current = ''
for i in words:
    # Add the next word
    current += i
    # If the current word is in the dictionary
    if dic.check(current):
        # Add it to the list
        lst.append(current)
        # Clear the current word
        current = ''
    # If the word is not in the dictionary we keep adding words to current

print(lst)

Answer 2

Notwithstanding the fact that this method is not very robust (you would miss "ham-burger", for example), the main error was that you didn't loop on the iterator, but on the list itself. Here is a corrected version.

Note that I renamed the variables to give them more expressive names, and I replaced the dictionnary check by a simple word in dic with a sample vocabulary - the module you import is not part of the standard library, which make your code as-is difficult to run for us who don't have it.

dic = {'love', 'friend', 'car', 'apple', 
       'computer', 'banana'}

words=['love', 'friend', 'car', 'apple', 'com', 'puter', 'vi']
words_it = iter(words)

valid_words = []

for word in words_it:
    if word in dic:
        valid_words.append(word)
    else:
        try:
            concacenated = word + next(words_it)
            if concacenated in dic:
                valid_words.append(concacenated)
        except StopIteration:
            pass

print (valid_words)
# ['love', 'friend', 'car', 'apple', 'computer']

You need the try ... except part in case the last word of the list is not in the dictionnary, as next() will raise a StopIteration in this case.