[英]PySide2 Non-Blocking QMessageBox doesn't show text
While my application does some time-consuming stuff, I want to display a message box to the user while the applications is busy.虽然我的应用程序做了一些耗时的事情,但我想在应用程序繁忙时向用户显示一个消息框。 I don't want any buttons (like
OK
or Cancel
) and I can't call exec_()
on the message box because that is blocking.我不想要任何按钮(如
OK
或Cancel
),而且我无法在消息框上调用exec_()
,因为那是阻塞的。
I checked a number of qt
sites and the code I need seems to boil down to:我检查了一些
qt
站点,我需要的代码似乎可以归结为:
message_box = QMessageBox()
message_box.setText(str('Reading Device, Please Wait...'))
message_box.show()
# do work here
message_box.close()
When I run the code, I get the message box, but without the text.当我运行代码时,我得到了消息框,但没有文本。 What am I doing wrong?
我究竟做错了什么?
I've included a working example below:我在下面包含了一个工作示例:
#!/usr/bin/env python3
import sys
import time
from PySide2.QtWidgets import (QLineEdit, QPushButton, QApplication,
QVBoxLayout, QDialog, QMessageBox)
class Form(QDialog):
def __init__(self, parent=None):
super(Form, self).__init__(parent)
self.button = QPushButton("Click Me")
layout = QVBoxLayout()
layout.addWidget(self.button)
self.setLayout(layout)
# Add button signal to dowork slot
self.button.clicked.connect(self.dowork)
def dowork(self):
message_box = QMessageBox()
message_box.setText(str('Reading Device, Please Wait...'))
message_box.show()
delay = 2.5
while delay:
sys.stdout.write('Working...\n')
time.sleep(0.5) # do some time-consuming stuff...
delay -= 0.5
message_box.close()
if __name__ == '__main__':
app = QApplication(sys.argv)
form = Form()
print('starting app...')
form.show()
sys.exit(app.exec_())
If you click the button, the message box pops up and is shown while the 'work' is being done.如果单击该按钮,消息框会弹出并在“工作”完成时显示。 When the 'work' is finished, the message box disappears again - as it should.
当“工作”完成时,消息框再次消失 - 应该如此。 But no text is shown in the message box.
但是消息框中没有显示任何文本。
There is a similar question here: qmessagebox-not-show-text-when-call-show , but that does not answer my question.这里有一个类似的问题: qmessagebox-not-show-text-when-call-show ,但这并没有回答我的问题。
You can not have a task that consumes a lot of time (more than 30 ms) since it blocks the GUI eventloop preventing Qt from doing its job normally, instead it uses a thread next to the signals to update the GUI from the other thread:您不能有一个消耗大量时间(超过 30 毫秒)的任务,因为它会阻止 GUI 事件循环,从而阻止 Qt 正常工作,而是使用信号旁边的线程从另一个线程更新 GUI:
import sys
import threading
import time
from PySide2 import QtCore, QtWidgets
class Form(QtWidgets.QDialog):
started = QtCore.Signal()
finished = QtCore.Signal()
def __init__(self, parent=None):
super(Form, self).__init__(parent)
self.button = QtWidgets.QPushButton("Click Me")
layout = QtWidgets.QVBoxLayout(self)
layout.addWidget(self.button)
# Add button signal to dowork slot
self.button.clicked.connect(self.on_clicled)
self._message_box = QtWidgets.QMessageBox()
self._message_box.setText(str('Reading Device, Please Wait...'))
self._message_box.setStandardButtons(QtWidgets.QMessageBox.NoButton)
self.started.connect(self._message_box.show)
self.finished.connect(self._message_box.accept)
@QtCore.Slot()
def on_clicled(self):
thread = threading.Thread(target=self.dowork, daemon=True)
thread.start()
def dowork(self):
delay = 2.5
self.started.emit()
while delay:
sys.stdout.write('Working...\n')
time.sleep(0.5) # do some time-consuming stuff...
delay -= 0.5
self.finished.emit()
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
form = Form()
print('starting app...')
form.show()
sys.exit(app.exec_())
You should almost certainly be using QProgressDialog.您几乎肯定应该使用 QProgressDialog。 Set minimum and maximum to zero for an 'indeterminate' look.
将最小值和最大值设置为零以获得“不确定”外观。
https://doc.qt.io/qt-5/qprogressdialog.html https://doc.qt.io/qt-5/qprogressdialog.html
Although forcing a redraw after your setText()
will probably work:尽管在
setText()
之后强制重绘可能会起作用:
self._message_box.repaint()
QtWidgets.QApplication.processEvents()
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