如何在保留有效位数的同时将 '0.00' 读作 Python 中的数字？

Question

How would i turn "0.00" into an int without getting invalid literal for int() with base 10: '0.00' error?

Heres my current code;

a = int('0.00')        # which gives me an error
a = int(float('0.00')) # gives me 0, not the correct value of 0.00

any suggestion would be appreciated!

Answer 1

If you need to track the number of significant digits past the decimal, neither float nor int is the correct way to store your number. Instead, use Decimal :

from decimal import Decimal
a = Decimal('0.00')
print(str(a))

...emits exactly 0.00 .

If doing this, you should probably also read the question Significant figures in the decimal module , and honor the accepted answer's advice.

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Of course, you can also round to a float or an int, and then reformat to the desired number of places:

a = float('0.00')
print('%.2f' % a)         # for compatibility with ancient Python
print('{:.2f}'.format(a)) # for compatibility with modern Python
print(f"{a:.2f}")         # for compatibility with *very* modern Python