将字典转换为元组

Question

I have the following dictionary:

myDict = {0:{'value1':25,'value2':2500},1:{'value1':35,'value2':1000}}

Which I would like converted into tuples looking like this:

((25,2500),(35,1000))

By using the below code create a one-dimensional tuple for the 0 key. However I would like to create a multi-dimensional tuple.

tup = tuple(myDict[0].values())

Answer 1

just do it by simple loop:

tuple(tuple(x.values()) for x in myDict.values())

if you need to sort result by dict key you can do it using sorted

tuple(tuple(v.values()) for k, v in sorted(myDict.items()))

Answer 2

This will return the tuple s in order,

>>> myDict
{0: {'value2': 2500, 'value1': 25}, 1: {'value2': 1000, 'value1': 35}}
>>> tuple((v['value1'], v['value2']) for k,v in sorted(myDict.items()))
((25, 2500), (35, 1000))
#   # order based on keyfunc ?
>>> tuple((v['value1'], v['value2']) for k,v in sorted(myDict.items(), key=lambda x: x[1]['value1']))
((25, 2500), (35, 1000))