[英]How to find the nearest coordinate in graph using Python
I want to find the nearest graph points using its coordinate values(x,y). 我想使用其坐标值(x,y)查找最近的图形点。 My Dataset is like 我的数据集就像
-15907.500 -19367.500
-15912.500 -19362.500
-15907.500 -19362.500
-15917.500 -19357.500
-15912.500 -19357.500
-15917.500 -19352.500
-15912.500 -19352.500
-16092.500 -19347.500
.For example we can take any point as a reference and by this reference We have to find closest near and another little distance coordinate and like that. 例如,我们可以将任何点作为参考,并且通过该参考,我们必须找到最接近的点和另一个小距离的坐标,像这样。
data
cols cols1
0 -15907.5 -19367.5
1 -15912.5 -19362.5
2 -15907.5 -19362.5
3 -15917.5 -19357.5
4 -15912.5 -19357.5
5 -15917.5 -19352.5
6 -15912.5 -19352.5
7 -16092.5 -19347.5
from sklearn.metrics.pairwise import euclidean_distances
euclidean_distances(data)
array([[ 0. , 7.07106781, 5. , 14.14213562,
11.18033989, 18.02775638, 15.8113883 , 186.07794066],
[ 7.07106781, 0. , 5. , 7.07106781,
5. , 11.18033989, 10. , 180.62391868],
[ 5. , 5. , 0. , 11.18033989,
7.07106781, 14.14213562, 11.18033989, 185.60711193],
[ 14.14213562, 7.07106781, 11.18033989, 0. ,
5. , 5. , 7.07106781, 175.28548143],
[ 11.18033989, 5. , 7.07106781, 5. ,
0. , 7.07106781, 5. , 180.27756377],
[ 18.02775638, 11.18033989, 14.14213562, 5. ,
7.07106781, 0. , 5. , 175.071414 ],
[ 15.8113883 , 10. , 11.18033989, 7.07106781,
5. , 5. , 0. , 180.06943105],
[186.07794066, 180.62391868, 185.60711193, 175.28548143,
180.27756377, 175.071414 , 180.06943105, 0. ]])
Reference:- 参考:-
To calculate the (Euclidean) distance between two points, you just subtract their coordinates, square, add, take the square root. 要计算两个点之间的(欧几里得)距离,只需减去它们的坐标,平方,加,取平方根即可。 In other words: 换一种说法:
def distance_between(x1, y1, x2, y2):
return sqrt((x1-x2)**2 + (y1-y2)**2)
Conveniently, the math
module provides the function hypot
that does this for us (a bit more efficiently since it uses C). 方便地, math
模块提供了功能hypot
,可以为我们完成此任务(由于使用C,因此效率更高)。
So now we can do this: 所以现在我们可以这样做:
from math import hypot
def closest_to(data, target):
x, y = target # Break `target` into coordinates
def distance(other_point): # How far is `other_point` from `target`?
x2, y2 = other_point # Break `other_point` into coordinates
return hypot(x-x2, y-y2) # Then calculate distance
return min(data, key=distance) # Now run through `data` and return whichever one has the lowest `distance` result
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