如何在Python中查找列表行和列索引

Question

I am trying to print row and column index in list.

I've used (loop below) this but Its one or the other..

a = [[0,0,1],
    [0,1,0],
    [1,0,0]]
def a():
x = 0
for sol in solutions:
    print(sol)
    for row in sol:
        print(row)

I am trying to print
(0,2) (1,1) (2,0)
Index of 1s
Thank You

Answer 1

You can use enumerate to generate indices for a list:

for row, sublist in enumerate(a):
    for column, item in enumerate(sublist):
        if item:
            print((row, column))

This outputs:

(0, 2)
(1, 1)
(2, 0)

Answer 2

If you like numpy you can turn it into a numpy array and use argwhere()

import numpy as np
a = [[0,0,1],
    [0,1,0],
    [1,0,0]]

a = np.array(a)
answer = np.argwhere(a==1)

This will output:

[[0 2]
 [1 1]
 [2 0]]