[英]How to empty an array in bash script
I am trying to get specific information from a bunch of files.我试图从一堆文件中获取特定信息。 Iterating over a list of files,
grep
ing for what I need.遍历文件列表
grep
我需要什么ING。 I know for sure that each grep
will give more than 1 result and I want to store that result in an array.我确信每个
grep
都会给出 1 个以上的结果,我想将该结果存储在一个数组中。 After finishing the work specific to file, I want to erase everything from arrays and start afresh for new file.完成特定于文件的工作后,我想从数组中擦除所有内容并重新开始新文件。
files_list=`ls`
for f in $files_list
do
echo $f
arr1=`cat $f | grep "abc" | grep "xyz"`
arr2=`cat $f | grep "pqr" | grep "mno"`
arr3=`cat $f | grep "df"`
for ((i=0; i<${#arr1[@]}; ++i))
do
printf "%s %s %s\n" "${arr1[i]}" "${arr2[i]}" "${arr3[i]}"
done
unset $arr1
unset $arr2
unset $arr3
done
So I used unset
to empty the array but it's giving error.所以我使用
unset
来清空数组,但它给出了错误。
line 49: unset: `x': not a valid identifier
I don't want to delete a particular member/index of array but entire array itself.我不想删除数组的特定成员/索引,而是删除整个数组本身。 Can anyone tell me how to do it?
谁能告诉我怎么做?
unset
works with variable names, not the values they keep. unset
适用于变量名称,而不是它们保留的值。 So:所以:
unset arr1
or, if you want to empty it:或者,如果你想清空它:
arr1=()
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