[英]Is there a cleaner way to handle (consecutive) exclusive if-statement in for-loop?
I'm new to Python (I've only used C) and I've discovered new loops such as for/else... So I wonder if I'm ignoring a cleaner way to handle this loop:我是 Python 的新手(我只使用过 C)并且我发现了新的循环,例如 for/else ......所以我想知道我是否忽略了一种更干净的方法来处理这个循环:
flag = 0
for i in range (n):
if not flag and condition:
statement_1
flag = 1
if flag and condition:
statement_2
I need to keep the for counting, because I know that at least one element will satisfy the condition, so when I find it I'll do statement_1.我需要保留 for 计数,因为我知道至少有一个元素会满足条件,所以当我找到它时我会做 statement_1。 Then if another element will satisfy the condition as well, I'll do statement_2.
然后,如果另一个元素也满足条件,我将执行 statement_2。
flag = False # I prefer booleans
for i in range(n):
if condition(i): # We always need it to be True
if not flag:
statement(i)
flag = True
else:
statement2(i)
So far this would work, but since you said there is at least one that satisfies the condition到目前为止,这是可行的,但是既然您说至少有一个满足条件
foo = range(n) # any iterable
iterfoo = iter(foo)
initial_value = next(i for i in iterfoo if condition(i))
statement(initial_value)
for i in iterfoo:
if condition(i):
statement2(i)
Now these both, (if I'm not missing something) should do the same thing, just in different ways, so it is your choice, although it also saves you 2 lines of code since you wont be doing the first line in your actual code, so I vote for the second snippet :D现在这两者(如果我没有遗漏一些东西)应该做同样的事情,只是方式不同,所以这是你的选择,虽然它也为你节省了 2 行代码,因为你不会在实际中做第一行代码,所以我投票给第二个片段:D
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