[英]How to approach pi in a circle
I have received an admission assignment for the Computer Science program, where I have to approach PI. 我已经收到了计算机科学计划的录取任务,在那里我必须攻读PI。 To calculate pi I have to make a ratio between the area of a square, a circle, the total number of dots and the number of dots within the circle.
为了计算pi,我必须在正方形,圆形的面积,圆点总数和圆点数之间求一个比率。
The formula of the area of a circle 圆的面积公式
radius^2 * π or diameter^2 * π / 4 半径^ 2 *π或直径^ 2 *π/ 4
The formula of the area of a square 平方面积的公式
2*radius^2 or diameter^2 2 *半径^ 2或直径^ 2
I had the formule ( M / N ) * 4
我有配方(M / N)* 4
This is how I got it: 这是我的方法:
(d^2 * π / 4) : d^2 = M : N (d ^ 2 *π/ 4):d ^ 2 = M:N
π / 4 = M / N π/ 4 = M / N
π = ( M / N ) * 4 π=(M / N)* 4
the problem is that I don't get pi as output, but about 14.2..
问题是我没有得到pi作为输出,而是大约14.2。
Does anyone know what I am doing wrong? 有人知道我在做什么错吗?
So in Processing I wrote the following code 所以在处理中,我编写了以下代码
float N = 0;
float M = 0;
void setup()
{
size(400, 400);
frameRate(90000);
background(255, 255, 255);
ellipse(200,200,400,400);
}
void draw()
{
/* Random x- en y-coordinate. */
float x = random(0,400);
float dx= (x-200);
float y = random(0,400);
float dy = (y-200);
float d = (float)(Math.sqrt(Math.pow(dx,2) + Math.pow(dy,2)));
/*Red in the circle*/
if(d <= 200 ){
stroke(255,0,0);
M++;
}
else{
stroke(0,255,0); /*green around the circle*/
N++;
}
point(x,y);
println
((M/N)*4);
}
The dots that land inside the circle also land in the square since the circle lays inside the square. 由于圆位于正方形内,落在圆内的点也落在正方形内。
You need to do 4*M/(M+N). 您需要执行4 * M /(M + N)。
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