如何计算行与另一个特定行之间的差异？

Question

I have a dataframe

full_name  x
q          1.5
q_1        1.3
q_2        1.2
q_3        1.3
r          1.5
r_1        1.3
r_2        1.2
r_3        1.3

and I'd like to create a new column which is the difference between the suffixed full names and their bases, such as the following:

full_name  x    x_diff
q          1.5  0
q_1        1.3  -0.2
q_2        1.2  -0.3
q_3        1.3  -0.2
r          1.5  0
r_1        1.3  -0.2
r_2        1.2  -0.3
r_3        1.3  -0.2

so, q - q , q_1 - q , q_2 - q , q_3 - q , and the same for r .

I've tried something like df['x_diff'] = df.res - df[df.main_name == df.full_name].x but that doesn't work. Any advice on what to do?

Answer 1

Create Series for matched main_name with full_name with DataFrame.set_index and then subtract Series.map ed main_name :

s =  df.loc[df.main_name == df.full_name].set_index('main_name')['x']

df['x_diff'] = df.x - df.main_name.map(s)
print (df)
  full_name main_name    x  x_diff
0         q         q  1.5     0.0
1       q_1         q  1.3    -0.2
2       q_2         q  1.2    -0.3
3       q_3         q  1.3    -0.2
4         r         r  1.5     0.0
5       r_1         r  1.3    -0.2
6       r_2         r  1.2    -0.3
7       r_3         r  1.3    -0.2

If always first values are equals in main_name with full_name per groups subtract Series created by GroupBy.first with GroupBy.transform :

df['x_diff'] = df.x - df.groupby('main_name')['x'].transform('first')

Answer 2

You can do it in 3 steps:

1. Groupby main_name
2. For each group: Create a new column (called for ex. x_shifted) that contains the previous value. For that, you can use df.shift(1) ( https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.shift.html )
3. For each group: Create the column x_diff that is the difference between x_shifted and x