[英]Reading lines from a file into variables in Bash
I'm creating a script to automate adding users from a text file in Unix using Bash 我正在创建一个脚本,使用Bash自动从Unix中的文本文件添加用户
I've read a file into a script which is being held in $FILE 我已经将文件读入了一个以$ FILE保存的脚本
The file is in the following format: e-mail;birthdate;groups;sharedFolder 该文件采用以下格式:电子邮件; birthdate; groups; sharedFolder
I want to ignore the first line in the file and read the data into variables 我想忽略文件中的第一行并将数据读入变量
I have already set the IFS to ';' 我已经将IFS设置为';' earlier. 早。 Currently I have 目前我有
sed 1d $FILE | while read EMAIL BIRTH GROUPS SHAREDFOLDER
do
echo "$EMAIL"
done < $FILE
But when I echo out the EMAIL variable, I get nothing 但当我回应EMAIL变量时,我什么也得不到
You are attempting to redirect standard input twice. 您正在尝试将标准输入重定向两次。 The pipeline and the <
can't both be connected to while read
. 管道和<
不能while read
连接。 On my Bash the <
wins: 在我的Bash上<
胜利:
bash$ echo moo | cat <<<bar
bar
Apparently you want simply 显然你想简单
sed 1d "$FILE" | while read -r EMAIL BIRTH GROUPS SHAREDFOLDER
do
echo "$EMAIL"
done
though this can meaningfully be reduced to just 虽然这可以有意义地减少到公正
sed 1d;s/;.*//' "$FILE"
You also really want to use lower case for your private variables , but that's a separate discussion. 您还真的想为您的私有变量使用小写 ,但这是一个单独的讨论。
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