[英]BASH - Reading Multiple Lines from Text File
i am trying to read a text file, say file.txt and it contains multiple lines. 我正在尝试读取一个文本文件,例如file.txt,它包含多行。
say the output of file.txt
is 说
file.txt
的输出是
$ cat file.txt
this is line 1
this is line 2
this is line 3
I want to store the entire output as a variable say, $text
. 我想将整个输出存储为变量,例如
$text
。
When the variable $text
is echoed, the expected output is: 回显变量
$text
,预期输出为:
this is line 1 this is line 2 this is line 3
my code is as follows 我的代码如下
while read line
do
test="${LINE}"
done < file.txt
echo $test
the output i get is always only the last line. 我得到的输出总是只有最后一行。 Is there a way to concatenate the multiple lines in file.txt as one long string?
有没有一种方法可以将file.txt中的多行连接为一个长字符串?
You can translate the \\n
(newline) to 您可以将
\\n
(换行符)转换为 (space):
(空间):
$ text=$(tr '\n' ' ' <file.txt)
$ echo $text
this is line 1 this is line 2 this is line 3
If lines ends with \\r\\n
, you can do this: 如果行以
\\r\\n
结尾,则可以执行以下操作:
$ text=$(tr -d '\r' <file.txt | tr '\n' ' ')
You have to append the content of the next line to your variable: 您必须将下一行的内容附加到变量中:
while read line
do
test="${test} ${LINE}"
done < file.txt
echo $test
Resp. RESP。 even simpler you could simply read the full file at once into the variable:
甚至更简单,您也可以一次将整个文件读入变量:
test=$(cat file.txt)
resp. RESP。
test=$(tr "\n" " " < file.txt)
If you would want to keep the newlines it would be as simple as: 如果您想保留换行符,它将很简单:
test=<file.txt
Another one: 另一个:
line=$(< file.txt)
line=${line//$'\n'/ }
test=$(cat file.txt | xargs)
echo $test
I believe it's the simplest method: 我相信这是最简单的方法:
text=$(echo $(cat FILE))
But it doesn't preserve multiple spaces/tabs between words. 但是它不会在单词之间保留多个空格/制表符。
Use arrays 使用数组
#!/bin/bash
while read line
do
a=( "${a[@]}" "$line" )
done < file.txt
echo -n "${a[@]}"
output: 输出:
this is line 1 this is line 2 this is line 3
See eg tldp section on arrays 参见例如关于阵列的tldp部分
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.