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如何从哈希创建Ruby GraphQL InputObject实例?

[英]How do I create a Ruby GraphQL InputObject instance from a Hash?

I have a GraphQL::Schema::InputObject subclass that I pass around inside my Rails server's GraphQL mutation handler. 我有一个GraphQL::Schema::InputObject子类,该子类在Rails服务器的GraphQL变异处理程序中传递。 I've separated out some of the parts of the code as separate units to test and would like to create an instance of this object in test. 我已经将代码的某些部分分离为要测试的单元,并希望在测试中创建此对象的实例。 How can I do this? 我怎样才能做到这一点?

My subclass looks like this: 我的子类如下所示:

class Foo < GraphQL::Schema::InputObject
  argument :bar, Int, required: true
end

I peeked inside the graphql-ruby tests and saw there's a constructor that take a Hash , so I tried: 我偷看了graphql-ruby测试, 发现有一个采用Hash的构造函数 ,所以我尝试了:

Foo.new({bar: 42}, context: OpenStruct.new(), defaults_used: Set.new())

but I get back: 但我回来了:

NoMethodError (undefined method `new' for nil:NilClass)

I'm using graphql-ruby 1.9.9. 我正在使用graphql-ruby 1.9.9。

Reading the tests more closely revealed that before you can call the constructor, you must first call to_graphql (documented in Extending the GraphQL-Ruby Type Definition System ). 仔细阅读测试后发现,在调用构造函数之前,必须首先调用to_graphql (在扩展GraphQL-Ruby类型定义系统中进行了介绍 )。 This method appears to bake out some schema/metaprogramming data. 该方法似乎可以烘焙一些模式/元编程数据。 Adding this line before the new call makes it work as I expect: new呼叫之前添加此行使其按预期工作:

Foo.to_graphql

However, the constructor doesn't appear to run any of the type coercions for the arguments: values are returned from the accessor methods verbatim. 但是,构造函数似乎没有对参数运行任何类型强制:值从访问方法中逐字返回。

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