[英]Interpolation for a 2D array
I was wondering if there is a way to interpolate a 2D array in python using the same principle used to interpolate a 1D array ( {np.interpolate} ). 我想知道是否有一种方法可以使用与插补1D数组({np.interpolate})相同的原理在python中插补2D数组。
So my aim is to increase the number of data points that is within my array ([1000,20] to [1000, 200] [Time_indexing, X]). 因此,我的目标是增加数组中的数据点数量([1000,20]到[1000,200] [Time_indexing,X])。
I am looking for a function that is capable of doing that. 我正在寻找能够做到这一点的功能。
A = np.array([[ 0.45717218, 0.44250104, 0.47812272, 0.49092173, 0.46002069],
[ 0.29829681, 0.26408021, 0.3709202 , 0.44823109, 0.49311853],
[ 0.05469835, 0.01048596, 0.17398291, 0.30088943, 0.39783137],
[-0.20463768, -0.24610673, -0.0713164 , 0.08406331, 0.22047102],
[-0.4074527 , -0.43573695, -0.31062521, -0.15750053, -0.00222392]])
This is a [5,5] array i want to interpolate it using a spacing of 0.01 hence the final product should be [500,500]. 这是一个[5,5]数组,我想使用0.01的间距对其进行插值,因此最终乘积应为[500,500]。
Thank you, 谢谢,
You could use interp2d : 您可以使用interp2d :
from scipy.interpolate import interp2d
f = interp2d(np.arange(0,500,100), np.arange(0,500,100), A)
f(np.arange(500), np.arange(500))
Output: 输出:
array([[ 0.45717218, 0.45702547, 0.45687876, ..., 0.46002069,
0.46002069, 0.46002069],
[ 0.45558343, 0.45543476, 0.45528609, ..., 0.46035167,
0.46035167, 0.46035167],
[ 0.45399467, 0.45384405, 0.45369343, ..., 0.46068265,
0.46068265, 0.46068265],
...,
[-0.4074527 , -0.40773554, -0.40801839, ..., -0.00222392,
-0.00222392, -0.00222392],
[-0.4074527 , -0.40773554, -0.40801839, ..., -0.00222392,
-0.00222392, -0.00222392],
[-0.4074527 , -0.40773554, -0.40801839, ..., -0.00222392,
-0.00222392, -0.00222392]])
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.