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如何使用fillConvexPoly从所有轮廓制作蒙版

[英]How to make mask from all contours with fillConvexPoly

I'm trying to make a mask from contours. 我正在尝试从轮廓制作遮罩。 Here's my full df 这是我的完整df

Here's a glimpse of first 7 rows 这是前7行的概览

>>> df
      contour.ID        xrT        yrT        xlT        ylT
1057          20  6259.2300  4620.7845  5670.1260  4651.4670
1058          20  6253.0935  4620.7845  5682.3990  4651.4670
1059          20  6253.0935  4633.0575  5694.6720  4657.6035
1060          20  6240.8205  4633.0575  5694.6720  4657.6035
1061          20  6228.5475  4645.3305  5700.8085  4669.8765
1062          20  6228.5475  4645.3305  5700.8085  4669.8765
1063          20  6216.2745  4645.3305  5713.0815  4669.8765

I can draw all contours I care about using a function. 我可以使用函数绘制所有关心的轮廓。

def display_all_contours(img, df, grouping_var):
    # display with matplotlib

    # Create figure and axes
    fig, ax = plt.subplots(1)

    # Display the image
    ax.imshow(img)

    # split by contour
    grouped_frame = df.groupby(grouping_var)
    li = [grouped_frame.get_group(x) for x in grouped_frame.groups]

    # for every contour
    for i in range(len(li)):
        poly = patches.Polygon(np.array([li[i].xrT, li[i].yrT]).T,
                               fill=False)
        ax.add_patch(poly)

    for i in range(len(li)):
        poly = patches.Polygon(np.array([li[i].xlT, li[i].ylT]).T,
                               fill=False, color="white")
        ax.add_patch(poly)

    return("Displaying " + str(len(np.unique(df[grouping_var]))) + " contours.")

This is the result of drawing the contorus on something that has the shape of my image. 这是在具有我图像形状的物体上绘制变形图的结果。

mask = np.zeros((9373, 12273), dtype=np.uint8)

display_all_contours(mask, df, "contour.ID")

在此处输入图片说明

Problem 问题

Now, I want to create a mask of all the polygons (in this case the left side). 现在,我想为所有多边形创建一个蒙版(在本例中为左侧)。 So I create a mask and burn into it each polygon using cv2.fillConvexPoly 因此,我创建了一个遮罩,并使用cv2.fillConvexPoly将每个多边形刻录到其中

mask = np.zeros((9373, 12273), dtype=np.uint8)

display_all_contours(mask, df, "contour.ID")

for poly in np.unique(df["contour.ID"]):
    # subset
    sub_df = df[df["contour.ID"] == poly]
    # burn into the mask
    # explicitly burn into the mask
    mask = cv2.fillConvexPoly(mask, np.array(sub_df[["xlT", "ylT"]], 'int32'), 1)

For some reason I don't understand, this does not produce the result I intended. 由于某种原因,我不明白,这并没有产生我想要的结果。

plt.imshow(mask)

在此处输入图片说明

Solved it, the function I was actually looking for is fillPoly 解决了它,我实际上正在寻找的功能是fillPoly

Replacing this line solves the problem 更换这条线解决了问题

# mind the np.array(..., "int32") is wrapped in [] because that's how fillPoly likes it
mask = cv2.fillPoly(mask, [np.array(sub_df[["xlT", "ylT"]], 'int32')], 1)

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