如何将相同的 integer 添加到 Rust 中向量的每个元素？

Question

In Python, if I have a list and want to add 10 to each element I would do:

bar = [2,4,5,6,7]
bar = [x + 10 for x in bar]

resulting in: [12,14,15,16,17] . How can this be done in Rust? Is the only way doing a for loop and going through each vector element?

Answer 1

The Rust way to do this is very similar to Python: use iterators! The rough equivalent to Python's list comprehension is iter::map to get the new elements, and iter::collect to collect into a new vector (or some other kind of collection).

So for example, if bar is a Vec<i32> (or any other primitive integer type) and you want to add 10 to each element, try

bar = bar.into_iter().map(|x| x + 10).collect();

(playground)

Alternatively, you could mutate the elements in-place with

bar.iter_mut().for_each(|x| *x += 10);

(playground)

This is basically like a for loop, but a bit more succinct. This is generally going to be more efficient than the first method since you don't need to allocate a new vector (a sufficiently smart compiler may be able to avoid this). The only downside is that this version is less flexible. The output still needs to be a vector; you couldn't switch to a hash set or what have you. You also wouldn't be able to keep a copy of the old vector. See below for some examples of what's possible.

fn main() {
    let mut bar = vec![2, 4, 5, 6, 7];
    // Overwrite the old vector
    bar = bar.into_iter().map(|x| x + 10).collect();
    println!("new bar: {:?}", bar);

    let bar = vec![2, 4, 5, 6, 7];
    // Make a completely new vector
    // Note that this works only because i32 implements the Copy trait,
    // so we can make copies of the elements of bar without any problems
    // In more general situations, we may need to clone each element
    let foo: Vec<_> = bar.iter().map(|&x| x + 10).collect();
    println!("old bar: {:?} (it's still around)", bar);
    println!("new foo: {:?}", foo);

    use std::collections::HashSet;
    let bar = vec![2, 4, 5, 6, 7];
    // transform the data and collect it into a HashSet
    // instead of a vector
    let bar: HashSet<_> = bar.into_iter().map(|x| x + 10).collect();
    println!("new bar: {:?} (note that now bar is unordered)", bar);

    let mut bar = vec![2, 4, 5, 6, 7];
    // Overwrite the old vector in place
    bar.iter_mut().for_each(|x| *x += 10);
    println!("new bar: {:?}", bar);
}

(playground)

Answer 2

This is basic code which illustrates how to do it the way the question assumes by default. It might be useful for beginners with Rust like me:

fn increment_mut(p: &mut Vec<i32>, to_add: i32){
    for i in 0..p.len() {
        p[i] += to_add;
    }
}

fn main() {
    let mut p = vec![2, 4, 5, 6, 7];
    increment_mut(&mut p, 10);

    // Print the complete vector in Debug.
    println!("{:?}", p)
}

$ cargo run
[12, 14, 15, 16, 17]

Using iter_mut

fn increment_mut2(p: &mut Vec<i32>, to_add: i32) {
    for x in p.iter_mut() {
        *x += to_add;
    }
}

fn main() {
    let mut p = vec![2, 4, 5, 6, 7];
    increment_mut2(&mut p, 10);

    // Print the complete vector in Debug.
    println!("{:?}", p)
}

$ cargo run
[12, 14, 15, 16, 17]