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如何获取列值的频率计数,按另一列中的分类值排序

[英]How to get frequency count for a column value, sorted by aa categorical value in another column

I have a pandas dataframe that includes two columns, vessel name and delay indicator.我有一个 pandas dataframe 包括两列,船只名称和延迟指示器。 Vessel name is a string name of a vessel, and delay indicator is either a 0 or 1 (boolean).船只名称是船只的字符串名称,延迟指示符是 0 或 1(布尔值)。

My DataFrame:我的 DataFrame:

df = pd.DataFrame({
    "Vessel.Name": ["Spirit of British Columbia", "Queen of New Westminster", "Spirit of Vancouver Island", "Coastal Celebration", "Spirit of British Columbia"],
    "Delay.Indicator":[0, 0, 0, 1, 0]
})

How it looks:它的外观:

Vessel.Name                 Delay.Indicator
Spirit of British Columbia  0
Queen of New Westminster    0
Spirit of Vancouver Island  0
Coastal Celebration         1
Spirit of British Columbia  0 

My goal is to get a DataFrame that includes each different ship name, and two new columns indicating its count, and its total number of "1" in delay indicator, for each different ship name.我的目标是获得一个 DataFrame,其中包括每个不同的船名,以及两个新列,指示其计数,以及延迟指示器中的“1”总数,用于每个不同的船名。 Not sure if there are pandas methods for this or if I should iterate through python lists?不确定是否有 pandas 方法或者我是否应该遍历 python 列表?

A simple groupby with aggregate functions applied should do the trick:应用聚合函数的简单 groupby 应该可以解决问题:

df.groupby("Vessel.Name")["Delay.Indicator"].agg(['count', sum])

Output: Output:

                            count   sum
Vessel.Name     
Coastal Celebration         1       1
Queen of New Westminster    1       0
Spirit of British Columbia  2       0
Spirit of Vancouver Island  1       0

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