如何停止一段时间或 if 语句多次运行？

Question

Ask the user to enter the number of students in the class. Thereafter ask the user to enter the student names and scores as shown. Output the name and score of the student with the 2nd lowest score.

NOTE: You may assume all students have distinct scores between 0 and 100 inclusive and there are at least 2 students

NOTE: You may only use what has been taught in class so far for this assignment. You are not allowed to use more advanced topics like lists, functions, dictionaries etc for this assignment.

I have gotten this far and I really don't know what to do know, is there an easies way to do this while staying inside the limits?

Is there a way to stop a while or if a statement after it runs one time? My solution is not working. I submitted the code below:

studentN = int(input('Enter the number of students: '))
i = 1
n = 1


studentna, studentsco = input('Please enter the student '+ str(n) +' name: '),int(input('Please the student ' + str(n) + ' score: '))

while i < studentN :
studentna2, studentsco2 = input('Please enter the student '+ str(n+1) +' name: '),int(input('Please the student ' + str(n+1) + ' score: '))
t = 1
if studentsco2 >= studentsco:
    t=1
    while t <= 1:
        studentna, studentsco = studentna2, studentsco2
        t += 1
        if studentN == 2:
            print (studentna, studentsco)
    while studentN == i+1:
        t = 1
        while t<= 1:
            if studentsco2 >= studentsco:
                studentna, studentsco = studentna2, studentsco2
    t += 1
elif studentsco2 <= studentsco:

    if studentN == 2:
        t = 1
        while t<= 1:
            t += 1
            print (studentna2, studentsco2)


    if studentN == i+1:
        t = 1
        while t<= 1:
            if studentsco2 <= studentsco:
                print (studentna, studentsco)
            t += 1
    else:
        studentna, studentsco = studentna2, studentsco2





print (studentna, studentsco)
n += 1
i += 1

Answer 1

All you have to do is to maintain the lowest and the secondlowest scores while the input is done:

studentN = int(input('Enter the number of students: '))

i = 1
studentsco = 0
studentna = ''
lowest_studentsco = 101
lowest_studentna = ''
secondlowest_studentsco = 101
secondlowest_studentna = ''

while i <= studentN :

    studentna, studentsco = input('Please enter the student '+ str(i) +' name: '),int(input('Please the student ' + str(i) + ' score: '))

    if studentsco < lowest_studentsco:
        secondlowest_studentsco = lowest_studentsco
        secondlowest_studentna = lowest_studentna
        lowest_studentsco = studentsco
        lowest_studentna = studentna
    elif studentsco < secondlowest_studentsco:
        secondlowest_studentsco = studentsco
        secondlowest_studentna = studentna

    i += 1

print (secondlowest_studentna, secondlowest_studentsco)

A known techinque is to initialize the variables for the lowest values with the highest possible value +1 so that they are changed immediately.

The conditions are self explanatory. Beware of the order of the variable assignment. Maybe you have learnt how to swap two variables a and b:) this is a little bit similar.

I think this assignment is good for learning and not for complaining.