[英]Neo4j: Cypher: How to remove labels by pattern?
I have a Neo4j database where each node has labels starting with underscore.我有一个 Neo4j 数据库,其中每个节点都有以下划线开头的标签。
For example, (:User,_User), (:Store,:_Store)
etc.例如,
(:User,_User), (:Store,:_Store)
等。
These underscore labels were generated by Spring Data Neo4j and now I want to get rid of them ( call db.schema()
returns them as a separate node in the schema).这些下划线标签是由 Spring 数据 Neo4j 生成的,现在我想摆脱它们(
call db.schema()
将它们作为模式中的单独节点返回)。
Goal to get only (:User), (:Store)
.只获取
(:User), (:Store)
的目标。
Is there any way to do that with some query?有没有办法通过一些查询来做到这一点?
If you remove the labels that start with underscores (eg _User
) from those nodes and replace them with values without the undescore then calls to db.schema()
should no longer return the values.如果您从这些节点中删除以下划线开头的标签(例如
_User
)并用不带取消划线的值替换它们,则对db.schema()
的调用不应再返回这些值。
You could do something like this...你可以做这样的事情......
MATCH (n:_User)
SET n:User
REMOVE n:_User
Updated answer based on feedback.根据反馈更新答案。 You could do something like this using APOC.
你可以使用 APOC 来做这样的事情。
// get all labels that start with underscore
CALL db.labels()
YIELD label AS old_label
WHERE old_label STARTS WITH '_'
WITH old_label, substring(old_label, 1, length(old_label)) AS new_label
// match the nodes for one of the underscore labels
MATCH (n)
WHERE old_label IN labels(n)
WITH old_label, new_label, collect(n) AS relabel_nodes
// call removeLabels with the list of nodes and list od labels to remove
CALL apoc.create.removeLabels(relabel_nodes, [old_label])
YIELD node AS removed_label_node
// call addLabels with the new label to add
WITH removed_label_node, new_label
CALL apoc.create.addLabels(removed_label_node, [new_label])
YIELD node AS added_label_node
RETURN added_label_node
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