[英]Inside a metal shader code, how to define an in/out parameter variable of a function?
I have this function:我有这个功能:
void myFunct(const int A, ?out? int B){B = B + A;}
How to declare B in such a way that the function can update its value and return it to the caller?如何以函数可以更新其值并将其返回给调用者的方式声明 B?
Metal is a C++ based programming language that allows you to pass a pointer to a function. Metal 是一种基于 C++ 的编程语言,它允许您将指针传递给函数。 To do so, simply declare the function parameter as a pointer type.
为此,只需将函数参数声明为指针类型。
void myFunct(const int A, device int *B)
{
*B = *B + A;
}
device int *C = 0;
myFunct(1, C);
You can also pass variable by reference:您还可以通过引用传递变量:
void myFunct(const int A, device int &B)
{
B = B + A;
}
device int *C = 0;
myFunct(1, *C)
or pointer by reference:或通过引用指针:
void myFunct(const int A, device int *&B)
{
*B = *B + A;
}
device int *C = 0;
myFunct(1, C);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.