简体   繁体   English

IndexError:在矩阵打印中列出超出范围的索引

[英]IndexError: list index out of range in matrix printing

in_num=int(input())
n_list=[[0 for x in range(in_num) for y in range(in_num)]]

print(n_list)
for row in range(in_num):
    for col in range(in_num):
        print(n_list[row][col],end='\t')
    print()  

When I run this code I get:当我运行此代码时,我得到:

5
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
0   0   0   0   0   
---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
<ipython-input-10-ef7ccb495ef4> in <module>
      4 for row in range(in_num):
      5     for col in range(in_num):
----> 6         print(n_list[row][col],end='\t')
      7     print()

IndexError: list index out of range

Why I am getting this error and how can I recover this error?为什么会出现此错误以及如何恢复此错误?

Hope this helps!希望这可以帮助!

can you update the following?你能更新以下内容吗?

n_list = [[0 for x in range(in_num) for y in range(in_num)]]

To below到下面

n_list = [[0 for x in range(in_num)] for y in range(in_num)]

Explanation: IMO, you are trying to create a 2D Matrix of zero's but you ended up creating a simple nested list of 1 element.说明:IMO,您正在尝试创建一个 0 的 2D 矩阵,但最终创建了一个包含 1 个元素的简单嵌套列表。

Instead of [[0, 0], [0, 0]] you are creating [[0, 0, 0, 0]].您创建的是 [[0, 0, 0, 0]],而不是 [[0, 0], [0, 0]]。 In this second output, the shape is this is 1 X 4 where as the first has 2 X 2.在第二个输出中,形状是 1 X 4,而第一个是 2 X 2。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM