PHP中基于日期过滤器过滤结果数组
[英]Filter result array based on date filter in PHP
问题描述
I have an array of results fetched from mysql database.
我有一个从 mysql 数据库中获取的结果数组。 I want to group those data based on dates as below:我想根据日期对这些数据进行分组，如下所示：
Input array:输入数组：
$resultSet = [
0 => [
'id' => 123,
'name' => 'ABC',
'start_date' => '2019-12-18 20:00:00'
],
1 => [
'id' => 124,
'name' => 'CDE',
'start_date' => '2019-12-19 20:00:00'
],
2 => [
'id' => 125,
'name' => 'TEST',
'start_date' => '2019-12-23 20:00:00'
],
3 => [
'id' => 126,
'name' => 'BWM',
'start_date' => '2019-12-18 20:00:00'
],
4 => [
'id' => 127,
'name' => 'XYZ',
'start_date' => '2019-12-19 20:00:00'
],
5 => [
'id' => 128,
'name' => 'GHJ',
'start_date' => '2019-12-21 20:00:00'
],
6 => [
'id' => 129,
'name' => 'GHJK',
'start_date' => '2019-12-22 20:00:00'
],
7 => [
'id' => 130,
'name' => 'GHL',
'start_date' => '2019-12-20 20:00:00'
],
8 => [
'id' => 131,
'name' => 'JKL',
'start_date' => '2019-12-25 20:00:00'
]
];
Output : Display all the list of products group by filters (Today, Tomorrow, This Weekend, Next Weekend etc.) Consider we are running script on Wednesday.输出：按过滤器（今天、明天、本周末、下周末等）显示所有产品列表。假设我们在星期三运行脚本。
Today : Display only record of index: 0, 3 (Today's Date: 2019-12-18)今天：只显示索引的记录：0, 3（今天的日期：2019-12-18）
Tomorrow : Display only record of index: 0, 3 (Tomorrow Date: 2019-12-19)明天：仅显示索引的记录：0、3（明天日期：2019-12-19）
This Weekend: Display only record of index: 5, 6, 7 (Friday, Saturday & Sunday: 2019-12-20, 2019-12-21, 2019-12-22)本周末：只显示第5、6、7的记录（周五、周六、周日：2019-12-20、2019-12-21、2019-12-22）
Next Week : Display only record of index: 2, 8 (Date: 2019-12-23, 2019-12-25) Next Week : 只显示索引的记录: 2, 8 (日期: 2019-12-23, 2019-12-25)
Result will display dynamically and every week different record will display as above.结果将动态显示，每周不同的记录将显示如上。
Sample Code Used:使用的示例代码：
$arrayList = [];
foreach($resultSet as $element){
$arrayList[$element->start_date][] = $element;
}
dd($arrayList);
Need to alter the above code to fetch the result as per the requirement below.需要更改上面的代码以按照下面的要求获取结果。
Framework : Laravel 5.2框架：Laravel 5.2
Requirements :要求：
- Script will either run on Wednesday or Thrusday (90% of time).脚本将在周三或周四（90% 的时间）运行。
- In case for some reason script did not run on those days.如果由于某种原因脚本在那些日子里没有运行。 We will manually run it on Friday.我们将在星期五手动运行它。 In that case Today is Friday and Saturday is Tomorrow .在这种情况下，今天是星期五，星期六是明天。 Also This Weekend will include data of Friday, Saturday and Sunday.本周末还将包括周五、周六和周日的数据。
- This Weekend will include data of Friday, Saturday & Sunday.本周末将包括周五、周六和周日的数据。
- Today, Tomorrow, This Weekend & Next Weekend label will be filtered from the " start_date ".今天、明天、本周末和下周末标签将从“开始日期”中过滤。
Expected OUTPUT :预期输出：
$output = [
'today' => [
0 => [
'id' => 123,
'name' => 'ABC',
'start_date' => '2019-12-18 20:00:00'
],
1 => [
'id' => 126,
'name' => 'BWM',
'start_date' => '2019-12-18 20:00:00'
]
],
'tomorrow' => [
0 => [
'id' => 124,
'name' => 'CDE',
'start_date' => '2019-12-19 20:00:00'
],
1 => [
'id' => 127,
'name' => 'XYZ',
'start_date' => '2019-12-19 20:00:00'
]
],
'this_weekend' => [
0 => [
'id' => 130,
'name' => 'GHL',
'start_date' => '2019-12-20 20:00:00'
],
1 => [
'id' => 128,
'name' => 'GHJ',
'start_date' => '2019-12-21 20:00:00'
],
2 => [
'id' => 129,
'name' => 'GHJK',
'start_date' => '2019-12-22 20:00:00'
]
],
'next_week' => [
0 => [
'id' => 125,
'name' => 'TEST',
'start_date' => '2019-12-23 20:00:00'
],
1 => [
'id' => 131,
'name' => 'JKL',
'start_date' => '2019-12-25 20:00:00'
]
]
];
I am running simple foreach loop in view page to display data.我在视图页面中运行简单的 foreach 循环来显示数据。 Please feel free to comment below if any queries.如果有任何疑问，请随时在下面发表评论。
4 个解决方案
解决方案1
2 2019-12-16 15:07:28
At the beginning you should define a useful date format for further comparing of dates:一开始你应该定义一个有用的日期格式来进一步比较日期：
$s = new DateTime(); // create date value
$s->modify('+2 days'); // in fact today is 2019-12-16
// but you've choose 2019-12-18
// you can comment this line
//echo $s->format('Y-m-d H:i:s').PHP_EOL; // today
$today = $s->format('Ymd'); // format 20191218
echo $today.' <- today'.PHP_EOL; // today
$nextmonday = $s->modify('next monday')->format('Ymd');
echo $nextmonday.' <- next monday'.PHP_EOL.PHP_EOL; // next monday, format 20191223
Then you need to make a foreach loop like this one:然后你需要做一个像这样的foreach循环：
foreach($resultSet as $rec){
$d = date('Ymd', strtotime($rec['start_date'])); // transform to format 20191218
$d2 = date('l', strtotime($rec['start_date'])); // name of the day
echo $d.' --- '.$d2.PHP_EOL;
if ($d == $today) { // 2019-12-18 == 2019-12-18
$res['today'][] = $rec;
} else if ($d - $today == 1) { // 2019-12-19 - 2019-12-18 == 1
$res['tomorrow'][] = $rec;
} else if (in_array($d2,['Friday','Saturday','Sunday']) && $d < $nextmonday){ // < 2019-12-23 and by day name
$res['this_weekend'][] = $rec;
} else if ($d >= $nextmonday){ // next week (not a weekend)
$res['next_weekend'][] = $rec;
}
}
Outputs will be:输出将是：
Array
(
[today] => Array
(
[0] => Array
(
[id] => 123
[name] => ABC
[start_date] => 2019-12-18 20:00:00
)
[1] => Array
(
[id] => 126
[name] => BWM
[start_date] => 2019-12-18 20:00:00
)
)
[tomorrow] => Array
(
[0] => Array
(
[id] => 124
[name] => CDE
[start_date] => 2019-12-19 20:00:00
)
[1] => Array
(
[id] => 127
[name] => XYZ
[start_date] => 2019-12-19 20:00:00
)
)
[next_weekend] => Array
(
[0] => Array
(
[id] => 125
[name] => TEST
[start_date] => 2019-12-23 20:00:00
)
[1] => Array
(
[id] => 131
[name] => JKL
[start_date] => 2019-12-25 20:00:00
)
)
[this_weekend] => Array
(
[0] => Array
(
[id] => 128
[name] => GHJ
[start_date] => 2019-12-21 20:00:00
)
[1] => Array
(
[id] => 129
[name] => GHJK
[start_date] => 2019-12-22 20:00:00
)
[2] => Array
(
[id] => 130
[name] => GHL
[start_date] => 2019-12-20 20:00:00
)
)
)
Note: the last array named as next_weekend , perhaps you need to rename it as next_week , cause it has dates just after your current weekend.注意：最后一个名为next_weekend数组，也许您需要将其重命名为next_week ，因为它的日期正好在您当前的周末之后。
I think you've understood an idea and will be able to add your further logic.我认为您已经理解了一个想法，并且能够添加您的进一步逻辑。
解决方案2
1 已采纳 2019-12-16 18:18:17
Well if you are using laravel then you can use the power of carbon and collection methods to solve such kinds of issues.好吧，如果您正在使用 laravel，那么您可以使用 carbon 和 collection 方法的力量来解决此类问题。
You can map the array key and group them by using carbon method.您可以使用 carbon 方法映射数组键并对其进行分组。 Check the following snippets will give you the exact result.检查以下片段将为您提供确切的结果。
date_default_timezone_set("Asia/Kolkata");
$resultSet = [
0 => [
'id' => 127,
'name' => 'XYZ',
'start_date' => '2020-01-03 20:00:00'
],
1 => [
'id' => 128,
'name' => 'GHJ',
'start_date' => '2020-01-04 20:00:00'
],
2 => [
'id' => 129,
'name' => 'GHJK',
'start_date' => '2020-01-05 16:00:00'
],
3 => [
'id' => 130,
'name' => 'GHL',
'start_date' => '2020-01-05 20:00:00'
],
4 => [
'id' => 131,
'name' => 'JKL',
'start_date' => '2020-01-18 20:00:00'
]
];
in case if you want the future date will be in "in_future" key.如果您希望将来的日期在“in_future”键中。
$output = collect($resultSet)->map(function ($value) {
$group_by_key = Carbon::parse($value['start_date']);
switch ($group_by_key) {
case $group_by_key->isToday():
$group_by_key = 'today';
break;
case $group_by_key->isTomorrow():
$group_by_key = 'tomorrow';
break;
case $group_by_key->isNextWeek():
$group_by_key = 'next_week';
break;
case $group_by_key->weekOfYear > Carbon::now()->addWeek()->weekOfYear:
$group_by_key = 'in_future';
break;
case $group_by_key->isWeekend():
$group_by_key = 'this_weekend';
break;
default:
$group_by_key = $group_by_key->format('l');;
break;
}
$value['group_by_key'] = $group_by_key;
return $value;
})->groupBy('group_by_key');
var_dump($output);
or in case if you want the future date will be in "next_week" key.或者，如果您希望将来的日期在“next_week”键中。
$output = collect($resultSet)->map(function ($value) {
$group_by_key = Carbon::parse($value['start_date']);
switch ($group_by_key) {
case $group_by_key->isToday():
$group_by_key = 'today';
break;
case $group_by_key->isTomorrow():
$group_by_key = 'tomorrow';
break;
case $group_by_key->weekOfYear > Carbon::now()->addWeek()->weekOfYear:
$group_by_key = 'next_week';
break;
case $group_by_key->isWeekend():
$group_by_key = 'this_weekend';
break;
default:
$group_by_key = $group_by_key->format('l');;
break;
}
$value['group_by_key'] = $group_by_key;
return $value;
})->groupBy('group_by_key');
var_dump($output);
解决方案3
0 2019-12-16 13:31:05
Try the bellow example试试下面的例子
$group = [];
foreach ($start_date as $item) {
if (!isset($group[$item['start_date']])) {
$group[$item['start_date']] = [];
}
foreach ($item as $key => $value) {
if ($key == 'start_date') continue;
$group[$item['start_date']][$key] = $value;
}
}
解决方案4
0 2019-12-16 14:15:04
I think you should make the array of different dates: Today, tomorrow, this weekend, nextweek我认为你应该制作不同日期的数组：今天，明天，这个周末，下周
Check link for time formats: https://carbon.nesbot.com/docs/检查时间格式的链接： https : //carbon.nesbot.com/docs/
$now = Carbon::now();
echo $now; // 2019-11-20 16:41:03
echo "\n";
$today = Carbon::today();
echo $today; // 2019-11-20 00:00:00
echo "\n";
$tomorrow = Carbon::tomorrow('Europe/London');
echo $tomorrow; // 2019-11-21 00:00:00
echo "\n";
Check your results with compare condition of dates and make arrays and combine them to one array.用日期的比较条件检查您的结果并制作数组并将它们组合成一个数组。
$totalarr = array('today'=>$todayarr,'tomorrow'=>$tomorrowarr,'thisweek'=>$thisweek,'nextweek'=>$nextweekarr);
print_r($totalarr);
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