[英]Return rows of df of particular month and year python pandas OutOfBoundsDatetime: Out of bounds nanosecond timestamp: 1-01-01 00:00:00
I am trying to create a function that will return rows pertaining only to particular month and year:我正在尝试创建一个函数,该函数将返回仅与特定月份和年份有关的行:
df df
order_date Type
2015-01-01 A
2017-09-01 A
2016-12-19 C
2019-11-23 D
2018-10-29 B
2017-12-31 B
2015-11-30 A
2015-08-30 B
2015-09-24 D
2015-01-27 E
Defining function定义函数
def return_data_month_year(month, year):
month = pd.to_datetime(month).month()
year = pd.to_datetime(year).year()
df = df[((df['order_date']).dt.strftime('%B') == month)&((df['order_date']).dt.strftime('%Y') ==
year)]
return df
Calling function调用函数
return_data_month_year('Jan','2015')
Expected output:预期输出:
order_date Type
2015-01-01 A
2015-01-27 E
I am getting error(Output):我收到错误(输出):
OutOfBoundsDatetime: Out of bounds nanosecond timestamp: 1-01-01 00:00:00
You don't have to call month = pd.to_datetime(month).month()
and year = pd.to_datetime(year).year()
.您不必调用month = pd.to_datetime(month).month()
和year = pd.to_datetime(year).year()
。
Also '%B'
returns full month name, eg. '%B'
返回完整的月份名称,例如。 January
. January
。 To return only abbreviation ( Jan
, Feb
, ...), use %b
:要仅返回缩写( Jan
、 Feb
、 ...),请使用%b
:
def return_data_month_year(df, month, year):
return df[((df['order_date']).dt.strftime('%b') == month)&((df['order_date']).dt.strftime('%Y') == year)]
# to convert column 'order_date' to datetime:
df['order_date'] = pd.to_datetime( df['order_date'] )
print( return_data_month_year(df, 'Jan','2015') )
Prints:印刷:
order_date Type
0 2015-01-01 A
9 2015-01-27 E
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