[英]Return multiple values in a function
I am doing a University project to create a plan ordering ticket program, so far these are what I have done:我正在做一个大学项目来创建一个计划订购票程序,到目前为止,这些是我所做的:
First, this is the function finding the seat type:首先,这是查找座位类型的函数:
def choosingFare():
print("Please choose the type of fare. Fees are displayed below and are in addtion to the basic fare.")
print("Please note choosing Frugal fare means you will not be offered a seat choice, it will be assigned to the ticketholder at travel time.")
listofType = [""] * (3)
listofType[0] = "Business: +$275"
listofType[1] = "Economy: +$25"
listofType[2] = "Frugal: $0"
print("(0)Business +$275")
print("(1)Economy +$25")
print("(2)Frugal: $0")
type = int(input())
while type > 2:
print("Invalid choice, please try again")
type = int(input())
print("Your choosing type of fare is: " + listofType[type])
if type == 0:
price1 = 275
else:
if type == 1:
price1 = 25
else:
price1 = 0
return price1, listofType[type]
And this is a function finding the destination:这是一个查找目的地的函数:
def destination():
print("Please choose a destination and trip length")
print("(money currency is in: Australian Dollars: AUD)")
print("Is this a Return trip(R) or One Way trip(O)?")
direction = input()
while direction != "R" and direction != "O":
print("Invalid, please choose again!")
direction = input()
print("Is this a Return trip(R) or One Way trip(O)?")
if direction == "O":
print("(0)Cairns oneway: $250")
print("(2)Sydney One Way: $420")
print("(4)Perth One Way: $510")
else:
print("(1)Cairns Return: $400")
print("(3)Sydney Return: $575")
print("(5)Perth Return: $700")
typeofTrip = [""] * (6)
typeofTrip[0] = "Cairns One Way: $250"
typeofTrip[1] = "Cairns Return: $400"
typeofTrip[2] = "Sydney One Way: $420"
typeofTrip[3] = "Sydney Return: $575"
typeofTrip[4] = "Perth One Way: $510"
typeofTrip[5] = "Perth Return: $700"
trip = int(input())
while trip > 5:
print("Invalid, please choose again")
trip = int(input())
if trip == 0:
price = 250
else:
if trip == 1:
price = 400
else:
if trip == 2:
price = 420
else:
if trip == 3:
price = 574
else:
if trip == 4:
price = 510
else:
price = 700
print("Your choice of destination and trip length is: " + typeofTrip[trip])
return price, typeofTrip[trip]
And this is the function calculating the total price:这是计算总价的函数:
def sumprice():
price = destination()
price1 = choosingFare()
price2 = choosingseat()
sumprice = price1 + price2 + price
print("How old is the person travelling?(Travellers under 16 years old will receive a 50% discount for the child fare.)")
age = float(input())
if age < 16 and age > 0:
sumprice = sumprice / 2
else:
sumprice = sumprice
return sumprice
The error I have:我有的错误:
line 163, in <module> main()
line 145, in main sumprice = sumprice()
line 124, in sumprice
sumprice = price1 + price2 + price
TypeError: can only concatenate tuple (not "int") to tuple
Can someone help me?有人能帮我吗? I am really stuck.
我真的被困住了。
I can't return all the我不能全部归还
return price, typeofTrip[trip]
. return price, typeofTrip[trip]
。sumprice = price1[0] + price2[0] + price3[0]
These functions return 2 values each: destination(), choosingFare(), choosingseat().这些函数各自返回 2 个值:destination()、choingFare()、chooseseat()。
Returning multiple values at once returns a tuple of those values: For example:一次返回多个值会返回这些值的元组:例如:
return price, typeofTrip[trip] # returns (price, typeofTrip[trip])
So while calculating the sum of all prices, you need to access price, price1, price2 from the tuples:因此,在计算所有价格的总和时,您需要从元组中访问 price、price1、price2:
sumprice = price1[0] + price2[0] + price3[0]
Alternatively: You can edit the code to return list/ dictionary or some other data structure as per your convenience.或者:您可以根据自己的方便编辑代码以返回列表/字典或其他一些数据结构。
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