[英]Want to create a sparse matrix like dataframe from a dataframe in pandas/python
I have a data frame like this我有一个这样的数据框
I want to convert it to something like this,note the ds is the day someone visited,and will have values from 0 to 31, for the days not visited it will show 0, and for the days visited it will show 1. It's kinda like sparse matrix,can someone help我想把它转换成这样,注意 ds 是有人访问的日期,值从 0 到 31,未访问的天数显示 0,访问的天数显示 1。有点像像稀疏矩阵,有人可以帮忙吗
Adding to the solution from @sim.从@sim 添加到解决方案。 By using the parameter columns, one can avoid the join.
通过使用参数列,可以避免连接。 the sparse=True parameter will return a sparse matrix.
sparse=True 参数将返回一个稀疏矩阵。 sparse=False will return a dense matrix.
sparse=False 将返回一个密集矩阵。
header = ["ds", "buyer_id", "email_address"]
data = [[23, 305, "fatin1bd@gmail.com"],
[22, 307, "shovonbad@gmail.com"],
[25, 411, "raisulk@gmail.com"],
[22, 588, "saiful.sdp@hotmail.com"],
[24, 664, "osman.dhk@gmail.com"]]
df = pd.DataFrame(data, columns=header)
df=pd.get_dummies(df,columns=['ds'],sparse=True)
If you use sparse=True, the result can be converted back to dense using sparse.to_dense() on the specific column.如果您使用 sparse=True,则可以在特定列上使用 sparse.to_dense() 将结果转换回密集。 For more details refer to User Guide
有关更多详细信息,请参阅用户指南
ds_cols=[col for col in df.columns if col.startswith('ds_')]
df=pd.concat([df[['buyer_id',"email_address"]],
df[ds_cols].sparse.to_dense()],axis=1)
Update: pd.get_dummies
now accepts sparse=True
to create a SparseArray
output.更新:
pd.get_dummies
现在接受sparse=True
来创建SparseArray
输出。
pd.get_dummies(s: pd.Series)
can be used to create a one-hot encoding like such: pd.get_dummies(s: pd.Series)
可用于创建像这样的 one-hot 编码:
header = ["ds", "buyer_id", "email_address"]
data = [[23, 305, "fatin1bd@gmail.com"],
[22, 307, "shovonbad@gmail.com"],
[25, 411, "raisulk@gmail.com"],
[22, 588, "saiful.sdp@hotmail.com"],
[24, 664, "osman.dhk@gmail.com"]]
df = pd.DataFrame(data, columns=header)
df.join(pd.get_dummies(df["ds"]))
output:输出:
ds buyer_id email_address 22 23 24 25
0 23 305 fatin1bd@gmail.com 0 1 0 0
1 22 307 shovonbad@gmail.com 1 0 0 0
2 25 411 raisulk@gmail.com 0 0 0 1
3 22 588 saiful.sdp@hotmail.com 1 0 0 0
4 24 664 osman.dhk@gmail.com 0 0 1 0
Just for added clarification: The resulting dataframe is still stored in a dense format.仅作补充说明:生成的数据帧仍以密集格式存储。 You could use
scipy.sparse
matrix formats to store it in a true sparse format.您可以使用
scipy.sparse
矩阵格式以真正的稀疏格式存储它。
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