Python 列表切片和索引，更好的方法

Question

I have a given number 15. I have to group it with each group of 5 elements, and get tuple as follows.

num = 15
div = int(15/3)


groups = list(zip(range(div), range(div, div+div), range(div+div, div+div+div)))

for group in groups:
   print (group)


(0, 5, 10)
(1, 6, 11)
(2, 7, 12)
(3, 8, 13)
(4, 9, 14)

It is printing expected result. However, what would be better way of doing it?

Answer 1

To specifically use slicing, you step by div in a slice of list(range(num)) :

num = 15
div = int(15/3)
num_list = list(range(num))

for idx in range(div):
    print(num_list[idx::div])

Edit: including num_list optimisation thanks to @Jordan Brière.

Answer 2

你可以在一行中很容易地做到这一点，也许我错过了一些东西

lst = [(i, i+div, i+2*div) for i in range(div)]

[(0, 5, 10), (1, 6, 11), (2, 7, 12), (3, 8, 13), (4, 9, 14)]