[英]c++ how to initialize global const variables sequentially
I have a problem with initializing global const variables:我在初始化全局常量变量时遇到问题:
int a;
const int b = a * a;
int main(int argc, char **argv) {
a = std::stoi(argv[1]);
...
}
I would like to pass values to a
and b
in the runtime.我想在运行时将值传递给
a
和b
。 However, the above code does not work for b
.但是,上面的代码不适用于
b
。 What should I do then?那我该怎么办? Thanks!!!
谢谢!!!
You can't and it's a real issue when using globals, which is why most large system developers (should) opt out of using the feature.您不能,而且在使用全局变量时这是一个真正的问题,这就是为什么大多数大型系统开发人员(应该)选择不使用该功能的原因。
My favorite approach:我最喜欢的方法:
int get_global_a(int initial_value=0) {
static int a = initial_value;
return a;
}
int get_global_b(int a_value=0) {
static int b = a_value * a_value;
return b;
}
/* Make sure this is the first line you execute in your program, but not before main! */
void initialize_all_globals(/* all necessary params */) {
int a = std::stoi(argv[1]);
get_global_a(a);
get_global_b(get_global_a());
}
You can initialize it with a static int like this at runtime.您可以在运行时使用像这样的静态 int 初始化它。 Later changes to the variable lead to a compile error:
稍后对变量的更改会导致编译错误:
#include <iostream>
static int hidden_b;
const int& b(hidden_b);
int main(int argc,char** argv) {
int a = std::stoi(argv[1]);
hidden_b = a*a;
std::cout << b << std::endl;
//b = 3; // compile error
// problems arise, if you change the hidden variable
/*hidden_b = 3;
std::cout << b << std::endl;*/
}
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