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Python,FFT 和 DC 偏移分析

[英]Python, FFT and DC offset analysis

I test an FFT on a square signal (100Hz, 0V-5V) of 50% duty cycle and i don't understand why my DC offset is huge?我在占空比为 50% 的方波信号(100Hz,0V-5V)上测试 FFT,但我不明白为什么我的 DC 偏移量很大?

In theory it should be 2.5V?理论上应该是2.5V?

Thanks, Best regards.谢谢,最好的问候。

The fundamental is ok and others harmonics are correct.基波正常,其他谐波正确。

square signal 100Hz, TTL compatible 0V-5V, 50% duty cycle方波信号100Hz,TTL兼容0V-5V,50%占空比

FFT, DC offset problem, fundamental ok, harmonics ok FFT,直流偏移问题,基波正常,谐波正常

from scipy.fftpack import fft
from scipy import signal
import matplotlib.pyplot as plt
import numpy as np

#
# configuration
# time analyse = L * (1/Fsample)
#
L = 512 # lenght buffer
Fsample = 2000 # frequency sample
Fsignal = 100 # frequency

#********************************

# perdiode sample
Tsample = 1.0/Fsample

# time vector, start = 0s, stop = 0.1024s, step = (0.1024s / (1/Fe))
t = np.linspace(0.0, L*Tsample, L)

# signal definition, DC offet = 2.5V, Amplitude = 2.5V
signal = 2.5 + 2.5*signal.square(2 * np.pi * Fsignal * t, 0.5)

# plot time signal
plt.subplot(2,1,1)
plt.plot(t, signal)

# fft of time signal
yf = fft(signal)

# time vector of fft 
xf = np.linspace(0.0, 1.0/(2.0*Tsample), L//2)

# plot spectral
plt.subplot(2,1,2)
plt.plot(xf, 2.0/L * np.abs(yf[0:L//2]))

On the last line, the normalization factor was wrong.在最后一行,归一化因子是错误的。

It was not 2/L but 1/L .不是2/L而是1/L

The correct normalization factor plt.plot(xf, 1.0/L * np.abs(yf[0:L//2]))正确的归一化因子plt.plot(xf, 1.0/L * np.abs(yf[0:L//2]))

The code work fine now !代码现在工作正常!

FFT correct amplitude FFT 正确幅度

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