您如何比较三个列表并将重复项添加到一个列表而将非重复项添加到另一个列表？

Question

I need to devise a way to compare all of the numbers in the three lists and should a number be present in all three lists - I have to add it to the matching_numbers list. If a number doesn't match any of the other numbers, then I have to add it to the unique_numbers list. I tried using a for loop, but I was only able to complete half of the equation and I wasn't sure as to how I could add all the unmatching numbers to the unique_numbers list. I also don't want any duplicates in my matching_numbers or unique_numbers list.

list_1 = []

list_2 = []

list_3 = []

matching_numbers = []

unique_numbers = []

countone = 0

counttwo = 0

countthree = 0

import random

name = input("Hello USER. What will your name be?")

print("Hello " + name + ". Welcome to the NUMBERS program.")

amountone = int(input("How many numbers do you wish to have for your first list? Please choose from between 1 and 15."))

while countone != amountone:
  x = random.randint(1, 50)
  list_1 += [x,]
  print(list_1)
  countone += 1

amounttwo = int(input("For your second list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while counttwo != amounttwo:
  x = random.randint(1, 50)
  list_2 += [x,]
  print(list_2)
  counttwo += 1

amountthree = int(input("For your third list, how many numbers do you wish to have? Please choose from between 1 and 15."))

while countthree != amountthree:
  x = random.randint(1, 50)
  list_3 += [x,]
  print(list_3)
  countthree += 1

for a in list_1:
    for b in list_2:
        for c in list_3:
          if a == b and b == c:
            matching_numbers = list(set(list_1) & set(list_2) & set(list_3))
          else:
            unique_numbers = 

Answer 1

This is the type of thing that Sets are perfect for. Unlike a list, where checking if something is present has a compexity of O(n) , set lookups are O(1) . Also, sets have methods already to check for intersections, differences, etc. So items in three sets can be computed as the intersection of the three:

all_numbers = set_1 | set_2 | set_3
matching_numbers = set_1 & set_2 & set_3
unique_numbers = all_numbers - matching_numbers