无论如何我可以简化我的 Python 程序吗？ 它运行但我觉得实现可能更简单

Question

This program asks a user at a bank for 3 inputs their bank id number, first name, and last name. If the user input is not the same as the default user (Ryan) then, the user is blocked from continuing, else they are welcomed.

Can I have a simpler implementation for this

f_name = input("What is your first name: ") 
print("You entered:" + f_name)
f_name = f_name

l_name = input("What is your last name: ") 
print("You entered:" + l_name)
l_name = l_name

bid = int(input("What is your bid: "))
print(f"You entered: {bid}")
bid = bid

if f_name == "Ryan" and l_name == "Monaghan" and bid == 12345:
    print("Welcome, Ryan")
else:
    print("Access Denied")

Answer 1

I am a big fan of loops and comparison on data objects instead of values specifically.

print('Please enter the following information:')
questions = [
    'First name',
    'Last name',
    'Bid'
]

answers = []

for q in questions:
    answers.append(input(q + ': '))

if answers == ['Ryan', 'Monaghan', '12345']:
    print('Welcome, Ryan')
else:
    print('Access Denied')

output:

Please enter the following information:
First name: Ryan
Last name: Monaghan
Bid: 12345
Welcome, Ryan

Answer 2

This is in response to a follow-up question as to how to provide a retry loop if the user input is rejected.

print('Please enter the following information:')
questions = [
    'First name',
    'Last name',
    'Bid'
]

answers = []

while(True): # Loop indefinately
    for q in questions:
        answers.append(input(q + ': '))

    if answers == ['Ryan', 'Monaghan', '12345']:
        print('Welcome, Ryan')
        break # Got a valid response, break out of the loop, note you may want to set a variable here as well to denote a successful response.
    else:
        print('Access Denied')
        r = input('Would you like to retry? (y/n):').lower().strip()
        if r != 'y' and r != 'yes':
            break # user does not want to try again, break out of loop