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strcat() 连接两个字符串

[英]strcat() concatenating to two strings

I am trying to concatenate a card ex."10" "1" "A" to the string "pile".我正在尝试将卡片 ex."10" "1" "A" 连接到字符串“pile”。 This is a very simplified version of Blackjack, so it is not concerned with the suits of the cards and deals one card at a time.这是一个非常简化的二十一点版本,因此它不关心牌的花色,一次发一张牌。

However when I run it, it adds the card to a pile string that was not passed into the method.但是,当我运行它时,它会将卡片添加到未传递给方法的堆字符串中。

I made a minimal recreation of the problem我对这个问题做了一个最小的娱乐

#include <stdio.h>
#include <stdlib.h> 
#include <time.h>
#include <string.h>

int placeCard(char *pile, char *card)
{
    //removed code for minimal recreation of problem
    //no piles finished
        strcat(pile, card);
        return 0;
}

int main()
{    
    char card[4];

    char pile1[] = "";
    char pile2[] = "";
    char pile3[] = "";
    char pile4[] = "";
    char pile5[] = "";

    char faces[13][4] = {" 2", " 3", " 4", " 5", " 6", " 7", " 8", " 9", " 10", " J", " Q", " K", " A"};

    while(1)
    {
        // print current state of game
        printf("Pile (1): %-20s \n",    pile1);
        printf("Pile (2): %-20s \n",    pile2);
        printf("Pile (3): %-20s \n",    pile3);
        printf("Pile (4): %-20s \n",    pile4);
        printf("Pile (5): %-20s \n\n",  pile5);

        //get random card
        int j = rand() % 52;
        //convert to string
        strcpy(card, faces[j/4]);

        printf("Drawn Card: %s\n\n", card);

        printf("Which pile to place card in? ");
        //assume valid input (1-5) for minmal reproduction of error
        int userPileChoice;
        scanf("%d", &userPileChoice);
        switch (userPileChoice)
        {
            case 1:
                placeCard(pile1, card);
                break;
            case 2:
                placeCard(pile2, card);
                break;
            case 3:
                placeCard(pile3, card);
                break;
            case 4:
                placeCard(pile4, card);
                break;
            case 5:
                placeCard(pile5, card);
                break;
            default:
                break;
        }

    }
}

And here is the output这是 output

Pile (1):                      
Pile (2):                      
Pile (3):                      
Pile (4):                      
Pile (5):                      

Drawn Card:  J

Which pile to place card in? 1
Pile (1):  J                   
Pile (2): J                    
Pile (3):                      
Pile (4):                      
Pile (5):                      

Drawn Card:  7

Which pile to place card in? 

I was thinking it could possibly be the switch case inside the while loop and break is messing it up somehow, but I tried researching it and didn't see anything wrong.我在想它可能是 while 循环内的开关盒,而 break 以某种方式把它搞砸了,但我试着研究它并没有发现任何问题。 Thanks for any help.谢谢你的帮助。

This: char pile1[] = "";这个: char pile1[] = ""; will allocate an array of size 1, which is only enough for the NUL terminator, which means that it is essentially useless.将分配一个大小为 1 的数组,仅够 NUL 终止符使用,这意味着它本质上是无用的。 Do the following change to the code:对代码进行以下更改:

#define SIZE 100
int main()
{
    char card[4];

    char pile1[SIZE] = "";
    // Same for the rest

This will solve your problem.这将解决您的问题。 But I recommend reading about dangers with strcat .但我建议阅读有关strcat的危险。 Here is a related post: strcat Vs strncat - When should which function be used?这是一个相关的帖子: strcat Vs strncat - 什么时候应该使用哪个 function? And it will work它会起作用

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