[英]Accessing strings from a array of strings in GNU Octave
How to access the whole elements hello
and ahoy
in Octave?如何在 Octave 中访问整个元素
hello
和ahoy
? Only the first character in each string is being printed.仅打印每个字符串中的第一个字符。
octave:1> s = ["hello";"ahoy"]
s =
hello
ahoy
octave:2> s(1)
ans = h
octave:3> s(2)
ans = a
Use cell arrays instead.请改用单元格 arrays。
octave:1> s = { 'hello'; 'ahoy' };
octave:2> s{1}
ans = hello
octave:3> s{2}
ans = ahoy
See https://octave.org/doc/v5.2.0/Cell-Arrays.html#Cell-Arrays参见https://octave.org/doc/v5.2.0/Cell-Arrays.html#Cell-Arrays
Check the size and type of s to understand what's going on:检查 s 的大小和类型以了解发生了什么:
octave:5> size(s)
ans =
2 5
octave:6> class(s)
ans = char
It's a 2x5 matrix of characters.它是一个 2x5 的字符矩阵。 To index, use matrix indexing.
要索引,请使用矩阵索引。 For example getting the first row:
例如获取第一行:
octave:7> s(1,:)
ans = hello
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.