如何将日期从 26-MAY-20 03.43.48.861000000 重新格式化为 'yyyy-mm-dd hh:mm:ss'？

Question

How would I convert '26-MAY-20 03.43.48.861000000' into 'yyyy-mm-dd hh:mm:ss' using datetime in Python?

Answer 1

So big picture, the goal is to create a date object out of the first string, and then format the date into the second string.

datetime.strptime will be your best friend here, along with datetime.strftime .

By referencing the library's format codes , we can put together a format of the first string.

from datetime import datetime

# I don't know why your datetime doesn't conform to the 1989 C standard but I'm just truncating it
may_26 = datetime.strptime('26-MAY-20 03.43.48.861000000'[:-3], "%d-%b-%y %H.%M.%S.%f")

output = datetime.strftime(may_26, "%Y-%m-%d %H:%M:%S")

I am making a few assumptions for you in the formatting, like assuming your datetime is on 24hr format, and stuff, so definitely check for yourself.

Answer 2

pandas.to_datetime would also parse the nanoseconds (I've modified the timestring to have some...):

import pandas as pd
t = pd.to_datetime('26-MAY-20 03.43.48.861000100', format="%d-%b-%y %H.%M.%S.%f")

t
Out[41]: Timestamp('2020-05-26 03:43:48.861000100')

t.microsecond
Out[42]: 861000

t.nanosecond
Out[43]: 100