在列表中查找元素

Question

from itertools import permutations as pm

perm = pm([1, 2, 3, 4])
pm_list = []

for i in list(perm):
    pm_list.append(i)

print(pm_list)
print(pm_list[0])

gives me:

[(1, 2, 3, 4), (1, 2, 4, 3), ... ]
(1, 2, 3, 4)

How can I work with the numbers in the second row (1, 2, 3, 4) ?

I have to address and to work with every single number in the bracket.

print(pm_list[0][0]) doesn't work.

Thanks in advance.

Answer 1

To use every number in the first result you can use a for loop.

for number in pm_list[0]:
   print (number)

Or if you want to do this for all results:

for result in pm_list:
   for number in result:
       print (number)