[英]How to convert a list of strings to a dict of lists where keys start with given substring
I have a list like this:我有一个这样的列表:
list = ['ID - ISO', 'CATA - CIT', 'CATA - CIT2', 'ID - ISO6', 'CATA - CIT', 'CATA - CIT2', 'CATA - CIT6', 'CATA - CIT8']
I would like to create a dictionary like this我想创建一个这样的字典
dict = {'ID - ISO': ['CATA - CIT', 'CATA - CIT2'],
'ID - ISO6': ['CATA - CIT', 'CATA - CIT2', 'CATA - CIT6', 'CATA - CIT8']}
So I developed this code but when I add the values, it is not working: the values are the same for all the ids.所以我开发了这段代码,但是当我添加值时,它不起作用:所有 id 的值都是相同的。
with open("/data/myfile") as openfile:
for line in openfile:
for single_line in line.split('\\'):
if line.startswith("ID"):
Dict[line] = None
elif line.startswith("CATA"):
for li in Dict:
Dict[li]=line
print Dict
You could use itertools.groupby()
:您可以使用itertools.groupby()
:
from itertools import groupby
lst = ['ID - ISO', 'CATA - CIT', 'CATA - CIT2','ID - ISO6', 'CATA - CIT', 'CATA - CIT2', 'CATA - CIT6', 'CATA - CIT8']
result = {}
for k,v in groupby(lst, lambda x: x.startswith('ID')):
if k:
key = next(v)
else:
result[key] = list(v)
print(result)
Which would yield这会产生
{
'ID - ISO': ['CATA - CIT', 'CATA - CIT2'],
'ID - ISO6': ['CATA - CIT', 'CATA - CIT2', 'CATA - CIT6', 'CATA - CIT8']
}
Additionally, do not call your variables after builtin types ( list
, dict
, tuple
, etc.) - you're effectively shadowing the functionality if you do.此外,不要在内置类型( list
、 dict
、 tuple
等)之后调用您的变量 - 如果您这样做,您实际上是在隐藏功能。
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