Python 将元组列表转换为具有多个元组值的字典

Question

I don't what to do with this because I can't append tuples and I just showed it with list as default

Dict = dict()
def convert(list_tup):
    for a,b,c in list_tup:
        letters = a,b 
        number = c
        Dict.setdefault(number,[]).append(letters)  
        # I only want a multiple tuple values not list of tuple
    return Dict
strings = [('w', 'x','2'), ('y', 'z', '3')]
print(convert(strings))

it prints {'2': [('w', 'x')], '3': [('y', 'z')]}

how can I add multiple tuples as value in one key?

I want my output to be like this:

{'2': ('w', 'x'), '3': ('y', 'z')}

Answer 1

The following dict comprehension should solve this

>>> {c: (a,b) for a,b,c in strings}
{'2': ('w', 'x'), '3': ('y', 'z')}

Answer 2

You can just make new entries in the output dictionary by keying c for the value (a,b) :

def convert(list_tup):
    d = {}
    for a,b,c in list_tup:
        letters = a,b 
        number = c
        d[c] = (a,b)
    return d

But Cory's answer is more