使用正则表达式提取嵌入在大括号内的 [] 内的内容

Question

I have a string in the following format

test_str = '{"keywords": {"Associate Director Information Technology Services": ["Director of Technology Services"]}}'

My Regex code below

import re
matches= re.findall(r'\{(.*?)\}',test_str)

gives the output

['"keywords": {"Associate Director  Information Technology Services": ["Director of Technology Services"]']

What change should I do in my Regex expression to output only

"Director of Technology Services"

Answer 1

re.findall(r"\[(.*?)\]", test_str)

print(re.findall(r"\[(.*?)\]", test_str)[0])

instead of escaping { and } you should escape [ and ] .
Alternative Solution using capturing of groups.

import re

regex = re.compile(r"\[(.*?)\]")
test_str = '{"keywords": {"Associate Director Information Technology Services": ["Director of Technology Services"]}}'

print(regex.search(test_str).group(1))

Output:

"Director of Technology Services"

Answer 2

Try using the below code:

import json
test_str = '{"keywords": {"Associate Director Information Technology Services": ["Director of Technology Services"]}}'
test_str_json = json.loads(test_str)
output = test_str_json["keywords"]["Associate Director Information Technology Services"][0]
print(output)

Output:

Director of Technology Services