如何将每一行放入从 c 程序中的文件读取的数组中？

Question

int main(int argc, char *argv)
{
    char filename[20]={};
    int count=0;

    if(argc==2)
    {
        strcpy(filename, argv[1]);
    }
    else
    {
        printf("Need 2 command line parameters\n");
    }

    FILE *fp=fopen(argv[1], "r");

    while(fgets(filename, 20, fp))
    {
        count++;
    }

    fseek(fp, 0, SEEK_SET);

    int ptr=(int)malloc(count*sizeof(int));
    while(fgets(filename, 20, fp))
    {
        ptr[i]=
    }

    return 0;

for example, my numbers in file are 19293 18239 19405 29302 10492 in each line, and I would like to put each line in an array. How do I do this? It doesn't have to be in a while loop.

Answer 1

I think your question is that you want to store the content you read as a string each line.Ok, there are serveal methods to realize it. If you don't care the effenciency, you can define a char pointer array as max as possible to contain all lines in your files. And you can do like this:

char* content[MAX_LINE] = { NULL };
char tmp[20];
char* ptr;
int i=0;
size_t ret;
FILE* fp;
fopen_s(&fp,"1.txt", "r");
while (fgets(tmp, 20, fp) != NULL)
{
    ret = strlen(tmp);
    ptr = (char*)malloc(ret+1);
    strcpy_s(ptr, ret+1, tmp);
    content[i++] = ptr;
}

And the better way is using pointer list.

Answer 2

If you want to read and store the whole content of your file in an array, you can do this in this simple way, though there are also other ways:

while( ( c = getc(file) ) != EOF )
  buffer[i++] = c;

where buffer is an char array of 1000 elements (it could be any number, you want), c is a char , and i is an int initialized with 0 .