R 将数据分组为具有度量变量的相等组

Question

I'm struggeling to get a good performing script for this problem: I have a table with a score, x, y. I want to sort the table by score and than build groups based on the x value. Each group should have an equal sum (not counts) of x. x is a metric number in the dataset and resembles the historic turnover of a customer.

      score x   y
0.436024136 3   435
0.282303336 46  56
0.532358015 24  34
0.644236597 0   2
0.99623626  0   4
0.557673456 56  46
0.08898779  0   7
0.702941303 453 2
0.415717835 23  1
0.017497461 234 3
0.426239166 23  59
0.638896238 234 86
0.629610596 26  68
0.073107526 0   35
0.85741877  0   977
0.468612039 0   324
0.740704267 23  56
0.720147257 0   68
0.965212467 23  0

Answer 1

a good way to do so is adding a group variable to the data.frame with cumsum. Now you can easily sum the groups with eg subset.

data.frame$group <-cumsum(as.numeric(data.frame$x)) %/% (ceiling(sum(data.frame$x) / 3)) + 1

remarks:

• in big data.frames cumsum(as.numeric()) works reliably
• %/% is a division where you get an integer back
• the '+1' just let your groups start with 1 instead of 0

thank you @Ronak Shah!